Answer:
The concentration of the NaOH solution CB = 0.251 M
Explanation:
The balanced equation of reaction is:
H2SO4 + 2NaOH ===> Na2SO4 + 2H2O
Using titration equation of formula
CAVA/CBVB = NA/NB
Where NA is the number of mole of acid = 1 (from the balanced equation of reaction)
NB is the number of mole of base = 2 (from the balanced equation of reaction)
CA is the concentration of acid = 0.1053 M
CB is the concentration of base = to be calculated
VA is the volume of acid = 17.88 mL
VB is the volume of base = 15.00mL
Substituting
0.1053×17.88/CB×15 = 1/2
Therefore CB =0.1053×17.88×2/15×1
CB= 0.251 M
Uhh there is only 1 answer choice sooo
Answer:
Is this an actual question that you had for school?
Explanation:
please mark my answer brainliest...
condition...pressure remains constant.
- for 720 ml temp is 15°...so for
- 960ml temp will be 15/720×960=20°...(.answer for 1st part...)
- for 900cmcube temp is 270°C...so for
- 300cmcube temp will be 270/900×300=90°....(answer for 2nd part)...
- I hope it helps the dear students...and if it is then let me know through ur comments...and please mark my answer as brainliest...plz...
