From the front door to his current position, Aaron's Distance is 4m. and his Displacement is 4m.
Distance is a measure of how far apart two objects or locations are using numbers. The distance can refer to a physical length in physics or to an estimate based on other factors in common usage. Sometimes, the symbol |AB| is used to represent the distance between two points.
A displacement is a vector in geometry and mechanics that have a length equal to the shortest distance between a point P's initial and final positions.
Given,
Length of path = 4m
Distance =?
Displacement =?
Distance is the length of the path and it has magnitude but no direction. The distance covered is 4m Displacement is the length of the path and it has magnitude and direction. Displacement is 4m towards the mailbox.
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The answer is c, because ball is falling so its gravitationl potential energy decreases, but it kinetic energy increases. Energy is always conserved.
The ball rolled for 13.2 s
<h3>Further explanation</h3>
Speed is scalar and no direction
A bowling ball rolls 33 m, with average speed = 2.5 m/s
So elapsed time :
In a closed system, the loss of momentum of one object is same as________ the gain in momentum of another object
according to law of conservation of momentum, total momentum before and after collision in a closed system in absence of any net external force, remains conserved . that is
total momentum before collision = total momentum after collision
P₁ + P₂ = P'₁ + P'₂
where P₁ and P₂ are momentum before collision for object 1 and object 2 respectively.
P'₁ - P₁ = - (P'₂ - P₂)
so clearly gain in momentum of one object is same as the loss of momentum of other object
Answer:
78.4 m
Explanation:
Using newton's equation of motion,
S = ut + 1/2gt²......................... Equation 1
Where S = Height, t = time, u = initial velocity, g = acceleration due to gravity.
Note: Taking upward to be negative, and down ward positive
Given: u = 49 m/s, t = 2.0 s, g = -9.8 m/s²
Substitute into equation 1
S = 49(2) - 1/2(9.8)(2)²
S = 98 - 19.6
S = 78.4 m
Hence the height of the ball two seconds later = 78.4 m