Answer:

Explanation:
The standard form of the 2nd order differential equation governing the motion of mass-spring system is given by

Where m is the mass, ζ is the damping constant, and k is the spring constant.
The spring constant k can be found by




The damping constant can be found by



Finally, the mass m can be found by



Where g is approximately 32 ft/s²

Therefore, the required differential equation is


The initial position is

The initial velocity is

Answer:
pascal
Explanation:
its obtained after either division or multiplication
Answer:
Explanation:We should know that weight = mass * gravity.
That is weight equals mass times gravity.
Gravity is a force of attraction between any two bodies in the universe. It is directly proportional to product of their masses and inversely proportional to the square of the distance between them.
Gravity is generally measured in terms of acceleration due to gravity, denoted as g. For Earth it is, 9.8 m/s². And for moon, it is about 1.62 m/s².
On Earth, your weight is 70 kg = W
W = mass x 9.8
70 = mass x 9.8
Your mass is 70/ 9.8
i.e approximately 7.14
Weight at the Moon, W' = 7.14 x 1.62
Hence, your weight on the surface of the moon is just 11.56 kg.
Congratulations, you've lost about 58.14 kilograms without any hard exercise. And you're as light as a Sweedish Vallhund! Cheers!
Answer:
The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object is increased, the acceleration of the object is decreased.
Explanation:
hope it helps pls give me brainless
Answer:
avriage force F = 2722.5 N
Explanation:
For this problem we can use Newton's second law, to calculate the average force and acceleration we can find it by kinematics.
vf² = v₀² - 2 ax
The final carriage speed is zero (vf = 0)
0 = v₀² - 2ax
a = v₀² / 2x
a = 1.1²/(2 0.200)
a = 3.025 m / s²
a = 3.0 m/s²
We calculate the average force
F = ma
F = 900 3,025
F = 2722.5 N