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insens350 [35]
3 years ago
15

As a particle moves 10.0 m along an electric field of strength 75 N/C, its electrical potential energy decreases by 4.8 × 10-16

J. What is the particle's charge?
Physics
1 answer:
Aleks04 [339]3 years ago
6 0

Answer:

6.4×10⁻¹⁹ C

Explanation:

From the question,

V = E×d.............. Equation 1

Where V = electric potential, E = Electric Field, d = distance moved by the particle.

Given: E = 75 N/C, d = 10 m.

Substitute into equation 1

V = 75×10 = 750 V.

Also Using,

W = qV.................. Equation 2

W = Work done by the particle when it moves, q = Particles charge

make q the subject of the equation,

q = W/V............ Equation 3

Given: W = 4.8×10⁻¹⁶ J, V = 750 V

Substitute into equation 3

q = 4.8×10⁻¹⁶/750

q = 6.4×10⁻¹⁹ C

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You are sitting behind the bus driver on a moving bus in relation to a person standing on the sidewalk you are what

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relative to sidewalk you are moving with the driver

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4 years ago
Two extremely large nonconducting horizontal sheets each carry uniform charge density on the surfaces facing each other. The upp
sashaice [31]

This problem refers to a parallel plate capacitor. There is an electric field between the two plates. The working equation to be used is the Gauss’s Law which is

Electric field = Surface charge density / ε0

The answer is -2.52 μC/m2.

8 0
3 years ago
A student project is required to be portable and hand held. It requires 6 V DC power at a current of 150 mA. The batteries for t
egoroff_w [7]

Answer:

a. 5 batteries b. 1050 mAh

Explanation:

Here is the complete question

A student project is required to be portable and hand held. It requires 6 V DC power at a current of 150 mA. The batteries for the power supply must last for a minimum of 7 hours of continuous operation. NiMH rechargeable batteries in AA size are to be used. A) How many batteries are needed? B) What mAh capacity should the batteries have?

Solution

A) How many batteries are needed?

Since the nominal voltage for a single NiMH battery is 1.2 V per battery and we require 6V DC power, we combine the batteries in series to obtain a total voltage of 6 V. The number of batteries required, n = total voltage/voltage per cell = 6V/1.2V per battery = 5 batteries

So, the number of batteries needed is 5.

B) What mAh capacity should the batteries have?

Since the batteries are in series, they would each deliver a current of 150 mA. Since we require a current of 150 mA for 7 hours, the number of milliampere-hours capacity mAh of batteries required is Q = It where I = current = 150 mA and t = time = 7 hours.

So, Q = It = 150 mA × 7 h = 1050 mAh.

So, the batteries should have a mAh of 1050 mAh

4 0
3 years ago
Complete the sentence
scoray [572]

The object is at rest.


This is due to the fact hwen two forces act upon each other on opposite sides, the movement of the object does not change due to the net force equaling 0.

6 0
3 years ago
A 40-W lightbulb is 1.9 m from a screen. What is the intensity of light incident on the screen? Assume that a lightbulb emits ra
valentinak56 [21]

Answer:

INTNESITY = 0.88W/m^{2}

Explanation:

given data:

power P =  40W

Distance of light bulb from screen is  R  = 1.9 m

The light intensity considered as  the light energy falling on the surface per unit area per unit time

Intensity of light can be determined by using following formula

intesnity = \frac{P} {4\pi R^{2}}

intesnity = \frac{40} {4\pi *1.9^{2}}

INTNESITY = 0.88W/m^{2}

8 0
3 years ago
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