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Mrrafil [7]
3 years ago
10

Sabrina decided to start selling lemonade on her street. The other kids in the neighborhood noticed that Sabrina was making a lo

t of money selling lemonade. These kids decided to open their own lemonade stand. When they opened their own lemonade stand, the equilibrium price ________ and the equilibrium quantity ________. Group of answer choices a. decreased; decreased b. stayed the same; stayed the same c. increased; decreased d. increased; increased e. decreased; increased

Physics
1 answer:
suter [353]3 years ago
6 0

Answer:

e. Decreased; Increased

Explanation:

The market equilibrium refers to the condition in which the price and the quantity are in equilibrium if the conditions of supply (what the producers offer) and demand (what the consumers buy) don't change.

In this case we have that as the other kids decide to sell more lemonade the amount of lemonade is going to increase (equilibrium quantity) and because of this the price is going to decrease (equilibrium price).

Then when the other kids open theirown lemonade stand, the equilibrium price <u>descreased</u> and the equilibrium quantity <u>increased.</u>

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The mitochondria is the powerhouse of the cell because it takes nutrients and breaks it down to provide energy for the cell.
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The greater the amplitude of a wave a. The quieter the sound b. The higher the frequency of the sound c. The dimmer the light in
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Answer:

The greater the amplitude the greater the energy.

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2 years ago
A brick and a feather fall to the earth at their respective terminal velocities. Which objectexperiences the greater force of ai
Karo-lina-s [1.5K]

Answer:

Under the reasonable assumption that the brick has more mass than the feather, the brick experiences a greater force of air friction.

Explanation:

<u>Objects at terminal velocity</u>, only under the influence of gravity, have maximized their speed and <u>have an acceleration of zero</u>.  Thus, neither object is accelerating.

Recall Newton's second law: \sum {\vec {F}}=m \vec {a}

Since acceleration for each object is zero, the sum of the force acting on each of those objects must also be zero.

Since the only forces acting on the objects are gravity and the force of air friction, in order to zero out, <u>the force of air friction must be equal in magnitude and opposite in direction to the force of gravity</u>.

Recall that near the surface of the earth, F_{gravity}=mg, so <u>the Force of Gravity acting on an object is directly proportional to the object's mass</u>.  <em>(A similar argument could be made even if this were not taking place on the surface of the earth, so long as the objects were the same distance from the object providing gravitational influence).</em>

If the masses of the objects are different, <u>the object with the greater mass will experience</u> a larger force of gravity, and hence <u>a larger force of air friction</u> at terminal velocity.  

Under the reasonable assumption that the brick has more mass than the feather, the brick experiences a greater force of air friction.

4 0
1 year ago
The mean diameters of Mars and Earth are 6.9 ✕ 103 km and 1.3 ✕ 104 km, respectively. The mass of Mars is 0.11 times Earth's mas
Roman55 [17]

Answer:

(a) Ratio of mean density is 0.735

(b) Value of g on mars 0.920 m,/sec^2

(c) Escape velocity on earth is 3.563\times 10^4m/sec

Explanation:

We have given radius of mars R_{mars}=6.9\times 10^3km=6.9\times 10^6m and radius of earth R_{E}=1.3\times 10^4km=1.3\times 10^7m

Mass of earth M_E=5.972\times 10^{24}kg

So mass of mars M_m=5.972\times\times 0.11 \times 10^{24}=0.657\times 10^{24}kg

Volume of mars V=\frac{4}{3}\pi R^3=\frac{4}{3}\times 3.14\times (6.9\times 10^6)^3=1375.357\times 10^{18}m^3

So density of mars d_{mars}=\frac{mass}{volume}=\frac{0.657\times 10^{24}}{1375.357\times 10^{18}}=477.69kg/m^3

Volume of earth  V=\frac{4}{3}\pi R^3=\frac{4}{3}\times 3.14\times (1.3\times 10^7)^3=9.198\times 10^{21}m^3

So density of earth d_{E}=\frac{mass}{volume}=\frac{5.972\times 10^{24}}{9.198\times 10^{21}}=649.271kg/m^3

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v=\sqrt{\frac{2GM}{R}}=\sqrt{\frac{2\times 6.67\times 10^{-11}\times 0.657\times 10^{24}}{6.9\times 10^6}}=3.563\times 10^4m/sec

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