Answer:
The middle, or the transitional metals
Explanation:
When naming elements, we use roman numerals to indicate what their charge is. The charge of an element is affected by their number of valence electrons (outermost electrons).
Transitional metals are generally <u>multivalent</u>, meaning that element has more than one possible number of valence electrons. This makes them have more than one possible charge. Roman numerals indicate which charge of that element is used/discussed.
Answer:Molarity tells us the number of moles of solute in exactly one liter of a solution. (Note that molarity is spelled with an "r" and is represented by a capital M.) We need two pieces of information to calculate the molarity of a solute in a solution: The moles of solute present in the solution
Explanation:
The correct answer that explains similarities between metal and Metalloids as regards the question is They both conduct electricity
- Metalloids can be regarded as elements that are similar to metals, this is because they posses valence orbitals which is described as highly delocalized over macroscopic volumes.
- As a result of this they can serve as electrical conductors.
- metalloids posses small energy gap which is located between the valence band as well as the conduction band, as a result of this they are considered as intrinsic semiconductors when compare to pure conductors like metal.
- Example of metal is Calcium, sodium and that of Metalloids are silicon and germanium
Therefore, metal and Metalloids are similar because of their conductivity of electricity
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there is more air near sea level
Answer:
V₂ =279.9 cm³
Explanation:
Given data:
Initial volume = 360 cm³
Initial temperature = 50°C
Initial pressure = 700 mmHg
Final volume = ?
Final temperature = 273 k
Final pressure = 1 atm
Solution:
According to general gas equation:
P₁V₁/T₁ = P₂V₂/T₂
Solution:
<em>We will convert the mmHg to atm.</em>
700/760 = 0.92 atm
<em>and °C to kelvin.</em>
50+273 = 323 K
P₁V₁/T₁ = P₂V₂/T₂
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 0.92 atm × 360 cm³ × 273 K / 323 K ×1 atm
V₂ = 290417.6 atm .cm³. K / 323 k. atm
V₂ =279.9 cm³