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Sidana [21]
3 years ago
9

A plane electromagnetic wave traveling in the positive direction of an x axis in vacuum has components Ex = Ey = 0 and Ez = (4.3

V/m) cos[(π × 1015 s-1)(t - x/c)].(a) What is the amplitude of the magnetic field component?
Physics
1 answer:
Ivan3 years ago
7 0

Answer:

B_{m}=1.4333*10^{-8}T

Explanation:

Given data

Ex = Ey = 0

Ez=(4.3V/m)cos(π×10¹⁵s⁻¹)(t-x/c)

To find

The amplitude of the magnetic field component

Solution

The electric field is given by:

Ez=(4.3V/m)cos(π×10¹⁵s⁻¹)(t-x/c)

Where Em=4.3 V/m

The magnitude of magnetic field is given by:

B_{m}=\frac{E_{m}}{c}

Where Em is amplitude of electric field and c is speed of light.

Substitute the given values

So

B_{m}=\frac{4.3V/m}{3.0*10^{8}m/s }\\B_{m}=1.4333*10^{-8}T

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