Question

A plane electromagnetic wave traveling in the positive direction of an x axis in vacuum has components Ex = Ey = 0 and Ez = (4.3 V/m) cos[(π × 1015 s-1)(t - x/c)].(a) What is the amplitude of the magnetic field component?

Answer 1

Answer:

$B_{m}=1.4333*10^{-8}T$

Explanation:

Given data

Ex = Ey = 0

Ez=(4.3V/m)cos(π×10¹⁵s⁻¹)(t-x/c)

To find

The amplitude of the magnetic field component

Solution

The electric field is given by:

Ez=(4.3V/m)cos(π×10¹⁵s⁻¹)(t-x/c)

Where Em=4.3 V/m

The magnitude of magnetic field is given by:

$B_{m}=\frac{E_{m}}{c}$

Where Em is amplitude of electric field and c is speed of light.

Substitute the given values

So

$B_{m}=\frac{4.3V/m}{3.0*10^{8}m/s }\\B_{m}=1.4333*10^{-8}T$