In a particular calcium atom, number of protons are 20, number of neutrons are 21 and that of electrons are 19. Here, protons are positively charged particles, neutrons are neutral and electrons are negatively charged particles. For a neutral atom, number of protons should be equal to number of electrons. If number of protons are more than number of electrons cation will form (positive charge) and if number of protons are less than number of electrons anion will form (negative charge).
Here, number of protons are 20 and that of electrons are 19, protons is 1 more than electron thus, Ca will get one positive charge and exist as Ca^{+}. Thus, the electrical charge on the atom will be +1.
Answer:
The final temperature = 848.7 K or 575.7 °C
Explanation:
Step 1: Data given
Temperature = 25.0 °C = 298 K
Volume = 158 mL = 0.158 L
The volume increases to 450 mL = 0.450 L
The pressure is constant
Step 2: Calculate the final temperature
V1/T1 = V2/T2
⇒with V1 = the initial volume = 0.158 L
⇒with T1 = the initial temperature = 298 K
⇒with V2 = the increased volume = 0.450 L
⇒with T2 = the new temperature = TO BE DETERMINED
0.158 L / 298 K = 0.450 L / T2
T2 = 0.450 L / (0.158L/298K)
T2 = 848.7 T
The final temperature = 848.7 K or 575.7 °C
Answer:
Types Descriptions
Flows occur when soil or rock acts like a liquid
Slumps a slice of material that moves as one piece along a curved surface
Landslides made up of unconsolidated rock; includes rockslides and avalanches
Creeps material that moves slowly down gently sloping areas
Explanation:
Googled it.
Answer:
0.3023 M
Explanation:
Let Picric acid = 
So,
+
⇄
+ 
The ICE table can be given as:
+
⇄
+ 
Initial: 0.52 0 0
Change: - x + x + x
Equilibrium: 0.52 - x + x + x
Given that;
acid dissociation constant (
) = 0.42
![K_a = \frac{[H_3O^+][Picric^-]}{H_{picric}}](https://tex.z-dn.net/?f=K_a%20%3D%20%5Cfrac%7B%5BH_3O%5E%2B%5D%5BPicric%5E-%5D%7D%7BH_%7Bpicric%7D%7D)
![0.42 = \frac{[x][x]}{0.52-x}}](https://tex.z-dn.net/?f=0.42%20%3D%20%5Cfrac%7B%5Bx%5D%5Bx%5D%7D%7B0.52-x%7D%7D)
![0.42 = \frac{[x]^2}{0.52-x}}](https://tex.z-dn.net/?f=0.42%20%3D%20%5Cfrac%7B%5Bx%5D%5E2%7D%7B0.52-x%7D%7D)
0.42(0.52-x) = x²
0.2184 - 0.42x = x²
x² + 0.42x - 0.2184 = 0 -------------------- (quadratic equation)
Using the quadratic formula;
; ( where +/- represent ± )
= 
= 
=
OR 
=
OR 
=
OR 
= 0.30225 OR - 0.72225
So, we go by the +ve integer that says:
x = 0.30225
x = [
] = [
] = 0.3023 M
∴ the value of [H3O+] for an 0.52 M solution of picric acid = 0.3023 M (to 4 decimal places).