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Verdich [7]
3 years ago
8

A passenger on a Ferris wheel moves in a vertical circle at a constant speed. Are the forces on her balanced?

Physics
1 answer:
vovikov84 [41]3 years ago
6 0

C.  The force is a constant change,  because her position on the Ferris wheel will constantly change.  I believe this is the answer, but use sources to double check.  I might use different vocab. then your teachers.  

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Star meaning plz :) I need help
Mamont248 [21]

a fixed luminous point in the night sky which is a large, remote incandescent body like the sun. or a conventional or stylized representation of a star, typically one having five or more points.
7 0
2 years ago
Which of these is another name for Newton's
dezoksy [38]
Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force.
5 0
2 years ago
Read 2 more answers
Set the initial bead height to 3.00 m. Click Play. Notice that the ball makes an entire loop. What is the minimum height require
strojnjashka [21]

Answer:

h> 2R

Explanation:

For this exercise let's use the conservation of energy relations

starting point. Before releasing the ball

       Em₀ = U = m g h

Final point. In the highest part of the loop

       Em_f = K + U = ½ m v² + ½ I w² + m g (2R)

where R is the radius of the curl, we are considering the ball as a point body.

      I = m R²

      v = w R

we substitute

       Em_f = ½ m v² + ½ m R² (v/R) ² + 2 m g R

       em_f = m v² + 2 m g R

Energy is conserved

       Emo = Em_f

       mgh = m v² + 2m g R

       h = v² / g + 2R

 

The lowest velocity that the ball can have at the top of the loop is v> 0

      h> 2R

3 0
2 years ago
Can some please help me with this?
Lerok [7]

1) Current

2)  Atoms

3) Wire

4) Negative

5) Neutron

6) Shock

7) Switch

8) Static

9) Volt

10) Battery

11) Dam

12) Thomas Edison

13) Benjamin Franklin

14) Alessandro Volta

15) Michael Faraday

I would say that these would be your correct answers, btw I'm doing something that is close to the same right now

Hope this helps :)

6 0
2 years ago
One of your summer lunar space camp activities is to launch a 1090 kg rocket from the surface of the Moon. You are a serious spa
Ludmilka [50]

Answer:

ΔP.E = 6.48 x 10⁸ J

Explanation:

First we need to calculate the acceleration due to gravity on the surface of moon:

g = GM/R²

where,

g = acceleration due to gravity on the surface of moon = ?

G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

M = Mass of moon = 7.36 x 10²² kg

R = Radius of Moon = 1740 km = 1.74 x 10⁶ m

Therefore,

g = (6.67 x 10⁻¹¹ N.m²/kg²)(7.36 x 10²² kg)/(1.74 x 10⁶ m)²

g = 2.82 m/s²

now the change in gravitational potential energy of rocket is calculated by:

ΔP.E = mgΔh

where,

ΔP.E = Change in Gravitational Potential Energy = ?

m = mass of rocket = 1090 kg

Δh = altitude = 211 km = 2.11 x 10⁵ m

Therefore,

ΔP.E = (1090 kg)(2.82 m/s²)(2.11 x 10⁵ m)

<u>ΔP.E = 6.48 x 10⁸ J</u>

7 0
3 years ago
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