Answer:
a) ![P_m=1.78\ Pa](https://tex.z-dn.net/?f=P_m%3D1.78%5C%20Pa)
b) ![f=79.5775\ Hz](https://tex.z-dn.net/?f=f%3D79.5775%5C%20Hz)
c) ![\lambda=7.076\ m](https://tex.z-dn.net/?f=%5Clambda%3D7.076%5C%20m)
d) ![v=563.06\ m.s^{-1}](https://tex.z-dn.net/?f=v%3D563.06%5C%20m.s%5E%7B-1%7D)
Explanation:
<u>Given equation of pressure variation:</u>
![\Delta P= (1.78\ Pa)\ sin\ [(0.888\ m^{-1})x-(500\ s^{-1})t]](https://tex.z-dn.net/?f=%5CDelta%20P%3D%20%281.78%5C%20Pa%29%5C%20sin%5C%20%5B%280.888%5C%20m%5E%7B-1%7D%29x-%28500%5C%20s%5E%7B-1%7D%29t%5D)
We have the standard equation of periodic oscillations:
![\Delta P=P_m\ sin\ (kx-\omega.t)](https://tex.z-dn.net/?f=%5CDelta%20P%3DP_m%5C%20sin%5C%20%28kx-%5Comega.t%29)
<em>By comparing, we deduce:</em>
(a)
amplitude:
![P_m=1.78\ Pa](https://tex.z-dn.net/?f=P_m%3D1.78%5C%20Pa)
(b)
angular frequency:
![\omega=2\pi.f](https://tex.z-dn.net/?f=%5Comega%3D2%5Cpi.f)
![2\pi.f=500](https://tex.z-dn.net/?f=2%5Cpi.f%3D500)
∴Frequency of oscillations:
![f=\frac{500}{2\pi}](https://tex.z-dn.net/?f=f%3D%5Cfrac%7B500%7D%7B2%5Cpi%7D)
![f=79.5775\ Hz](https://tex.z-dn.net/?f=f%3D79.5775%5C%20Hz)
(c)
wavelength is given by:
![\lambda=\frac{2\pi}{k}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cfrac%7B2%5Cpi%7D%7Bk%7D)
![\lambda=\frac{2\pi}{0.888}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cfrac%7B2%5Cpi%7D%7B0.888%7D)
![\lambda=7.076\ m](https://tex.z-dn.net/?f=%5Clambda%3D7.076%5C%20m)
(d)
Speed of the wave is gives by:
![v=\frac{\omega}{k}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B%5Comega%7D%7Bk%7D)
![v=\frac{500}{0.888}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B500%7D%7B0.888%7D)
![v=563.06\ m.s^{-1}](https://tex.z-dn.net/?f=v%3D563.06%5C%20m.s%5E%7B-1%7D)
I think its all four of them could be wrong but try all four !!!!!!
The crate would slide forward
I believe the answer would be zero because the q1 and q2 are equal on opposite sides and it
hope this helps
Answer: A a decrease of 8000
Explanation: 10,500 - 2,500= 8000