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seraphim [82]
3 years ago
6

The distance required for a car to come to a stop will vary depending on how fast the car is moving. Suppose that a certain car

traveling down the road at a speed of 20 m / s 20 m/s can come to a complete stop within a distance of 80 m 80 m . Assuming the road conditions remain the same, what would be the stopping distance required for the same car if it were moving at speeds of 10 m / s 10 m/s , 40 m / s 40 m/s , or 5 m / s 5 m/s ?
Physics
1 answer:
djyliett [7]3 years ago
5 0

Answer:

Explanation:

If F be the force acting on the car to stop it

work done by force = change in kinetic energy

F X 80 = 1/2 m x 20²

F = 2.5 m

If speed is 10m/s

for distance d , the equation is

F x d = 1/2 x m x 10²

2.5 m x d = 1/2 x m x 10²

d = 20 m

If velocity is 40 m /s

F x d = 1/2 x m x 40²

2.5m x d = 1/2 m x 1600

d = 320 m

For v = 5 m/s

F x d = 1/2 m x 5²

2.5 m x d = 1/2 m x 5²

d = 5 m .

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Use the information from the graph to answer the question.
galina1969 [7]

The displacement of the object as determined from the velocity-time graph is 562.5 m.

<h3>What is a velocity-time graph?</h3>

A velocity-time graph is a graph of the velocity of an object plotted in the vertical or y-axis of the graph against the time taken on the horizontal or x-axis.

The displacement of an object can be obtained from its velocity-time graph by calculating the total area under the graph.

The total area under the graph = area of triangle + area of rectangle

Area of triangle = b*h/2 =

Area of triangle = 25 * (35 - 10)/2 = 312.5 m

Area of rectangle = l * b

Area of rectangle = 10 * 25 = 250 m

Total area = (312.5 + 250) m

Total area = 562.5 m

Therefore, the displacement of the object is 562.5 m

In conclusion, the total area of a velocity-time graph gives the displacement.

Learn more about velocity-time graph at: brainly.com/question/28064297

#SPJ1

5 0
1 year ago
What distance does a biker travel if he rides at a constant speed or 22 m/s for 45 seconds?
vredina [299]

Answer:

it would be 990 m.

Explanation:

22 m/s x 45 seconds.

5 0
3 years ago
7. When initially-unpolarized light passes through three polarizing filters, each oriented at 45 degree angles from the precedin
GREYUIT [131]

Answer:

Explanation:

Let the intensity  of unpolarised light be I₀ . After passing through the first polarising filter , the intensity  is I₀ / 2 .

After second filter , the intensity  will be  I₀ / 2 x cos²45 =  I₀ / 4

After third filter , the intensity will be I₀ / 4  x cos²45 = I₀ / 8 .

So,

1 / 8 the of initial light passes through the last filter .

7 0
3 years ago
A particle of mass M moves along a straight line with initial speed vi. A force of magnitude F pushes the particle a distance D
LenaWriter [7]

Answer:

vf = √(vi²+2*(F/m)*D)

Explanation:

Given

Mass of the particle: M

Initial speed of the particle: vi

Force: F

Distance: D

We can apply the formula

F = M*a   ⇒    a = F/m

then we use the equation

vf = √(vi²+2*a*D)

⇒  vf = √(vi²+2*(F/m)*D)

6 0
3 years ago
What is the value of the normal force if the coefficient of kinetic friction is 0.22 and the kinetic frictional force is 40 newt
ipn [44]
Hope this helps you!

5 0
3 years ago
Read 2 more answers
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