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seraphim [82]
3 years ago
6

The distance required for a car to come to a stop will vary depending on how fast the car is moving. Suppose that a certain car

traveling down the road at a speed of 20 m / s 20 m/s can come to a complete stop within a distance of 80 m 80 m . Assuming the road conditions remain the same, what would be the stopping distance required for the same car if it were moving at speeds of 10 m / s 10 m/s , 40 m / s 40 m/s , or 5 m / s 5 m/s ?
Physics
1 answer:
djyliett [7]3 years ago
5 0

Answer:

Explanation:

If F be the force acting on the car to stop it

work done by force = change in kinetic energy

F X 80 = 1/2 m x 20²

F = 2.5 m

If speed is 10m/s

for distance d , the equation is

F x d = 1/2 x m x 10²

2.5 m x d = 1/2 x m x 10²

d = 20 m

If velocity is 40 m /s

F x d = 1/2 x m x 40²

2.5m x d = 1/2 m x 1600

d = 320 m

For v = 5 m/s

F x d = 1/2 m x 5²

2.5 m x d = 1/2 m x 5²

d = 5 m .

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Answer:

The break even cost is $0.0063825

Explanation:

Break-even cost is the amount of money, or change in value, which equates to the amount at which an asset must be sold to equal the cost of acquiring it. For easier understanding it can be thought the amount of money for which a product or service must be sold to cover the costs of manufacturing or providing it.

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Price of bulb = $0.39

Wattage consumption of bulb per hours = 60

Life of CFL = 24 years

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Wattage consumption of CFL per hour = 15

Calculate the Equated Annual Cost (EAC) of bulb

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PVIFA 11%, 2 years = [1 – {(1 + 0.11)^(-2)}]/0.11 = 1.712523 (for 2 years)

PVIFA 11%, 24 years = [1 – {(1 + 0.11)^(-24)}]/0.11 = 8.348136 (for 2 years)

<u>Calculate the EAC of bulb</u>

EAC = {- P - (W/1000 x H x C) x (PVIFA 11%, 2 years)}/ (PVIFA 11%, 2 years)

EAC = {- 0.39 - (60/1000 x H x C) x (1.712523)}/ (1.712523)

EAC = {-0.39 – (51.37570 x C)}/ 1.712523, <em>consider this equation 1</em>

<u>Calculate the EAC of CFL</u>

EAC = {- P - (W/1000 x H x C) x (PVIFA 11%, 24 years)}/ (PVIFA 11%, 24 years)

EAC = {- 3.10 - (15/1000 x 500 x C) x (8.348136)}/ (8.348136)

EAC = {-3.10 – (62.61102 x C)}/8.348137, <em>consider this equation 2</em>

<u>Equate 1 and 2 to find the amount of C</u>

{-0.39 – (51.37570 x C)}/ 1.712523 = {-3.10 – (62.61102 x C)}/8.348137

{-0.39 – (51.37570 x C) x 8.348137} = {-3.10 – (62.61102 x C) x 1.712523}

C = $0.0063825

Thus, the break- even cost per kilo – watt is $0.0063825

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The average coefficient of linear expansion of copper is 1.7 10-5 (°c)−1. the statue of liberty is 93 m tall on a summer morning
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Let the rise in temperature be 5^0C

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