The displacement of the object as determined from the velocity-time graph is 562.5 m.
<h3>What is a velocity-time graph?</h3>
A velocity-time graph is a graph of the velocity of an object plotted in the vertical or y-axis of the graph against the time taken on the horizontal or x-axis.
The displacement of an object can be obtained from its velocity-time graph by calculating the total area under the graph.
The total area under the graph = area of triangle + area of rectangle
Area of triangle = b*h/2 =
Area of triangle = 25 * (35 - 10)/2 = 312.5 m
Area of rectangle = l * b
Area of rectangle = 10 * 25 = 250 m
Total area = (312.5 + 250) m
Total area = 562.5 m
Therefore, the displacement of the object is 562.5 m
In conclusion, the total area of a velocity-time graph gives the displacement.
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Answer:
Explanation:
Let the intensity of unpolarised light be I₀ . After passing through the first polarising filter , the intensity is I₀ / 2 .
After second filter , the intensity will be I₀ / 2 x cos²45 = I₀ / 4
After third filter , the intensity will be I₀ / 4 x cos²45 = I₀ / 8 .
So,
1 / 8 the of initial light passes through the last filter .
Answer:
vf = √(vi²+2*(F/m)*D)
Explanation:
Given
Mass of the particle: M
Initial speed of the particle: vi
Force: F
Distance: D
We can apply the formula
F = M*a ⇒ a = F/m
then we use the equation
vf = √(vi²+2*a*D)
⇒ vf = √(vi²+2*(F/m)*D)