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2 years ago

What is the difference between heterochromatin and euchromatin.

Chemistry

2 answers:

Anestetic [448]2 years ago

6 0

Answer:

Heterochromatin is the part of the chromosome without DNA coding genes and Euchromatin is the part of the chromosome with coding genes.

Explanation:

Euchormatin is the part of the chromosome which is rich with gene concentration and participates in the transition process. Heterochromatin is th area with a darkly stained DNA specific strand and is a condensed state.

qwelly [4]2 years ago

5 0

Answer:

The main difference between the two is euchromatin is genetically active while heterochromatin is genetically inactive

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You find a mysterious white powder in your kitchen. It could be cream of tartar (pH=5), sugar (pH=7), baking soda (pH=8), or dra

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The pH indicators to be used are Phenolphthalein, Red cabbage, Bromthymol blue and Congo red.

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Indicators are substances which change color as the pH of a medium changes.

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Learn more about pH indicators at: brainly.com/question/13779537

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2 years ago

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2 years ago

Determine whether or not the mixing of each of the two solutions indicated below will result in a buffer.

WARRIOR [948]

Part A

75.0 mL of 0.10 M HF; 55.0 mL of 0.15 M NaF

This combination will form a buffer.

Explanation

Here, weak acid HF and its conjugate base F- is available in the solution

Part B

150.0 mL of 0.10 M HF; 135.0 mL of 0.175 M HCl

This combination cannot form a buffer.

Explanation

Here, moles of HF = 0.15 x 0.1 = 0.015 moles

Moles of HCl = 0.135 x 0.175 = 0.023

Since HCl is a strong acid and the number of HCl is higher than HF. This prevents the dissociation of HF and the conjugate base F- will not be available in the solution

Part C

165.0 mL of 0.10 M HF; 135.0 mL of 0.050 M KOH

This combination will form a buffer.

Explanation

Moles of HF = 0.165 x 0.1 = 0.0165 moles

Moles of KOH = 0.135 x 0.05 = 0.00675 moles

Moles of KOH is not sufficient for the complete neutralization of HF. Thus weak acid HF and its conjugate base F- is available in the solution and form a buffer

Part D

125.0 mL of 0.15 M CH3NH2; 120.0 mL of 0.25 M CH3NH3Cl

This combination will form a buffer

Explanation

Here, weak acid CH3NH3+ and its conjugate base CH3NH2 is available in the solution and form a buffer

Part E

105.0 mL of 0.15 M CH3NH2; 95.0 mL of 0.10 M HCl

This combination will form a buffer

Explanation

Moles of CH3NH2 = 0.105 x 0.15 = 0.01575 moles

Moles of HCl = 0.095 x 0.1 = 0.0095 moles

Thus the HCl completely reacts with CH3NH2 and converts a part of the CH3NH2 to CH3NH3+. This results weak acid CH3NH3+ and its conjugate base CH3NH2 is in the solution and form a buffer

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3 years ago