Answer:
5.16×10¹⁵ s
Explanation:
Considering the rotational motion of the Earth,
K.E. = ω² where, I = MR²
= MR²ω² ---------(1) where ω = angular velocity of Earth
To find ω,
ω = 2π/T where T = time period of Earth
= 2π/(60×60×24) = 7.27×10^-5 rad/s
Substituting the values in (1),
K.E. = 0.4×(6×10^24)×(6400000)²×(7.27×10^-5)²
= 5.16×10²⁹ J
To calculate possible time,
Time = Energy/ Power
= 5.16×10²⁹ / 10¹⁴
= 5.16×10¹⁵ s
It's easy raising the barbell.
We balance the enthalpy absorbed by the steel and the enthalpy lost by wood. In this case, we use mCp ΔT to describe the problem. Cp (W) is 4 Cp(S). assuming the same mass,
mCp(W) ΔT1 = <span>mCp(S) ΔT2
</span> 4* <span>ΔT1 = 40
</span><span>ΔT1 = 10. Hence the temperature of the wood is decreased by 10 degrees</span>