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julsineya [31]
2 years ago
9

15 points..please write a short answer lIke 2 lines .​

Physics
1 answer:
marusya05 [52]2 years ago
6 0

When the Sun is slightly below the horizon, its light moves from less dense air to more dense air and gets refracted towards the normal. Because of this atmospheric refraction, the Sun appears to be above the horizon when it is actually slightly below the horizon.

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Tala wants to create a sound echo. She can create the echo using a pane of glass or a carpet square. Which one does she choose?
Alisiya [41]
Carpet asorbs sound, so glass should make it echo.
7 0
2 years ago
Two ropes are attached to a 35 kg object. The first rope applies a force of 20 N and the second applies a force of 55 N. If the
Goshia [24]

Answer:

a=1.672\ m.s^{-2}

Explanation:

Given:

  • mass of the object, m=35\ kg

forces by two mutually perpendicular ropes of the attached to the object:

  • F_x=20\ N
  • F_y=55\ N

<u>Now we find the resultant force effect due to the two given forces:</u>

F=\sqrt{F_x^2+F_y^2}

F=\sqrt{(20)^2+(55)^2}

F=58.52\ N

<u>Now the acceleration will be due to this resultant force:</u>

a=\frac{F}{m}

a=\frac{58.52}{35}

a=1.672\ m.s^{-2}

3 0
3 years ago
Read 2 more answers
In separate experiments, a large number of particles (all with the same charge, but with a wide variety of masses and speeds) ar
likoan [24]

Answer:

  they have the same mass

Explanation:

The force applied by the field is a function of the charge and velocity, so the acceleration experienced by a particle will be dependent upon its mass. Particles in orbits with the same radius are exhibiting the same acceleration, so must have the same mass.

7 0
3 years ago
A long cylindrical capacitor is made of a central wire of radius a = 2.50 mm surrounded by a conducting shell of radius b = 7.50
asambeis [7]

Answer:

The capacitance per unit length is 5.06\times10^{-11}\ F/m

(b) is correct option.

Explanation:

Given that,

Radius a= 2.50 mm

Radius b=7.50 mm

Dielectric constant = 3.68

Potential difference = 120 V

We need to calculate charge per length for the capacitance

Using formula of charge per length

\lambda=\dfrac{4\pi\epsilon_{0}\Delta V}{2 ln(\dfrac{r_{2}}{r_{1}})}

Put the value into the formula

\lambda=\dfrac{120}{9\times10^{9}\times2 ln(\dfrac{7.50\times10^{-3}}{2.50\times10^{-3}})}

\lambda=6.068\times10^{-9}\ C/m

We know that,

\lambda=\dfrac{Q}{L}

We need to calculate the capacitance per unit length

Using formula of capacitance per unit length

C=\dfrac{\dfrac{Q}{L}}{\Delta V}

C=\dfrac{6.068\times10^{-9}}{120}

C=5.06\times10^{-11}\ F/m

Hence, The capacitance per unit length is 5.06\times10^{-11}\ F/m

7 0
3 years ago
Matthew is looking at two different atoms. One has 8 protons and 10 neutrons. The other substance has 8 protons and 12 neutrons.
Lunna [17]

Answer:

They are the same element.

Explanation:

Atom >>>>> Proton >>>> Neutron

A >>>>>>>> 8 >>>>>>>>> 10

B >>>>>>>> 8 >>>>>>>>> 12

From the table above we can see that both atoms have the same proton number.

Therefore, they are the same element because they have the same proton number which means that they have the same atomic number. The element in this case is existing as an isotope in that the atoms have the same proton number but different neutron number.

6 0
2 years ago
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