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Yuri [45]
3 years ago
15

When you use a crowbar to lift a large rock, you are working against the force called

Chemistry
1 answer:
Ne4ueva [31]3 years ago
7 0
Gravity. The rock is being pushed down and you are counteracting that force with a crowbar pushing it upward.
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For the main group elements( excluding the transition elements) , is it necessary to memorize the type of ion each element makes
vagabundo [1.1K]
Yes, you should memorize them. While it is easy to predict them by looking at a periodic table, you should still have a strong grasp of simpler chemistry such as this before more challenging topics are taught.
3 0
3 years ago
Which of the following is NOT a characteristic of stars? A) Size B) temperature C) texture D) color
Lynna [10]

Answer:

C

Explanation:

Characteristics used to classify stars include color, temperature, size, composition, and brightness.

7 0
3 years ago
Clear selection
marin [14]

The molarity of the acid given the data from the question is 0.30 M

<h3>Balanced equation </h3>

2HNO₃ + Ba(OH)₂ —> Ba(NO₃)₂ + 2H₂O

From the balanced equation above,

  • The mole ratio of the acid, HNO₃ (nA) = 2
  • The mole ratio of the base, Ba(NO₃)₂ (nB) = 1

<h3>How to determine the molarity of the acid</h3>

From the question given above, the following data were obtained:

  • Volume of acid, HNO₃ (Va) = 39.7 mL
  • Volume of base, Ba(NO₃)₂ (Vb) = 24 mL
  • Molarity of base, Ba(NO₃)₂ (Cb) = 0.250 M
  • Molarity of acid, HNO₃ (Ma) =?

MaVa / MbVb = nA / nB

(Ma × 39.7) / (0.25 × 24) = 2

(Ma × 39.7) / 6 = 2

Cross multiply

Ma × 39.7 = 6 × 2

Ma × 39.7 = 12

Divide both side by 39.7

Ma = 12 / 39.7

Ma = 0.30 M  

Learn more about titration:

brainly.com/question/14356286

#SPJ1

8 0
2 years ago
What scientist established the law of octaves?
Hoochie [10]

I believe it was John Newlands.  

Hope that helped

6 0
3 years ago
What mass of hcl gas must be added to 1.00 l of a buffer solution that contains [aceticacid]=2.0m and [acetate]=1.0m in order to
Paraphin [41]
PH of acidic buffer = pKa + log [CH₃COONa - HCl] / [CH₃COOH + HCl]
pKa of CH₃COOH = 4.74
Concentration of acetic acid in buffer = 2.0 M
Concentration of sodium acetate = 1.0 M
Concentration of HCl must add = x
pH = 4.74 + log (1-x) / (2+x) = 4.11
x = concentration of HCl must be added = 0.43 M
number of moles of HCl = M * V = 0.43 * 1 = 0.43 mol
mass of HCl must be added = 0.43 * 36.5 = 15.7 g
 
3 0
3 years ago
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