When you use a crowbar to lift a large rock, you are working against the force called

Answer:

a fossil

Explanation:

Petrified wood is a fossil. It forms when plant material is buried by sediment and protected from decay due to oxygen and organisms. Then, groundwater rich in dissolved solids flows through the sediment, replacing the original plant material with silica, calcite, pyrite, or another inorganic material such as opal.

6 0

4 years ago

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What mass of calcium chloride is needed to prepare 2.657 L of a 1.56 M solution?

inna [77]

Answer:

459.126 grams of calcium chloride is needed to prepare 2.657 L of a 1.56 M solution

Explanation:

Molarity is a measure of the concentration of a solute in a solution that indicates the amount of moles of solute that appear dissolved in one liter of the mixture. In other words, molarity is the number of moles of solute that are dissolved in a given volume.

The Molarity of a solution is determined by the following expression:

$Molarity=\frac{number of moles of solute}{volume}$

Molarity is expressed in units $\frac{moles}{liter}$

In this case:

Molarity: 1.56 M= 1.56 $\frac{moles}{liter}$
Number of moles of calcium chlorine= ?
Volume= 2.657 liters

Replacing:

$1.56 M=\frac{Number of moles of calcium chlorine}{2.657 liters}$

Solving:

Number of moles of calcium chlorine= 1.56 M* 2.657 liters

Number of moles of calcium chlorine= 4.14 moles

In other side, you know:

Ca: 40 g/mole
Cl: 35.45 g/mole

Then the molar mass of the calcium chloride CaCl₂ is:

CaCl₂= 40 g/mole + 2* 35.45 g/mole= 110.9 g/mole

Now it is possible to apply the following rule of three: if in 1 mole there is 110.9 g of CaCl₂, in 4.14 moles of the compound how much mass is there?

$mass=\frac{4.14 moles*110.9g}{1 mole}$

mass= 459.126 g

<u><em>459.126 grams of calcium chloride is needed to prepare 2.657 L of a 1.56 M solution</em></u>

3 0

3 years ago

Where would we find the water with the highest concentration of pollution

RUDIKE [14]

The answer is A: Point z

7 0

3 years ago

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Determine if the individual bonds in each compound are polar or nonpolar.

almond37 [142]

Answer:

See explanation

Explanation:

For SCl2

S = 2.8, Cl = 3.16 difference = 0.4 polar

H2S

H = 2.2 S= 2.8 difference = 0.6 polar

CF4

C = 2.55, F= 3.98 difference = 1.43

This compound is nonpolar irrespective of the difference in electronegativity because the molecule is symmetrical

PCl5

P= 2.19, Cl= 3.16 difference = 0.97

This compound is nonpolar irrespective of the difference in electronegativity because the molecule is symmetrical

CH4

C = 2.55 H = 2.2 difference = 0.35 the molecule is nonpolar

CaBr2

Ca= 1 Br= 2.96 difference = 1.96

The compound is not just polar but ionic in nature due to large electronegativity difference between the bonding atoms

SF2

S = 2.8 F= 3.98 difference = 1.18

The molecule is polar

CO2

C= 2.55 O= 3.44 difference = 0.89

This compound is nonpolar irrespective of the difference in electronegativity because the molecule is symmetrical

NH3

N= 3.04 H = 2.2 difference =0.84

The molecule is polar

NaS

Na= 0.93 S = 2.8 difference = 1.87

The compound is not just polar but ionic in nature due to large electronegativity difference between the bonding

4 0

3 years ago

Consider the following reaction at equilibrium: 2CO2 (g) ↔ 2CO (g) + O2 (g) ∆H° = -514 kJ Le Châtelier's principle predicts that

Elza [17]

<h3><u>Answer;</u></h3>

increase the partial pressure of CO2

<h3><u>Explanation;</u></h3>

2CO(g) + O2(g) -------> 2CO2(g) + heat

Removel of Oxygen makes the equilibrium to move towards the left side (reactants) because the reactants concentration is decreasing. According to the LeChâtelier’s principle equilibrium moves towards the lower concentration.
When the partial pressure of any of the gaseous reactants or of the products is increased, the position of equilibrium is shifted so as to decrease its partial pressure. In this case, the removal of oxygen causes a shift to to the left which causes an increase in the partial pressure of CO2.

6 0

3 years ago

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