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hichkok12 [17]
3 years ago
5

Nitrogen has two isotopes. One has an atomic mass of 14.003

Chemistry
1 answer:
Ilia_Sergeevich [38]3 years ago
6 0

Answer:

d= 14.007 amu

Explanation:

Abundance of N¹⁴ = 99.63%

Abundance of N¹⁵ = 0.37%

Atomic mass of N¹⁴ = 14.003 amu

Atomic mass of N¹⁵ = 15.000 amu

Average atomic mass = ?

Solution:

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass = (14.003 × 99.63)+(15.000× 0.37) /100

Average atomic mass =  1395.12 + 5.55 / 100

Average atomic mass  = 1400.67/ 100

Average atomic mass = 14.007 amu.

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Answer:

The answer to your question is below

Explanation:

Propane is a hydrocarbon that has only single bonds in its structure so it is an alkane.

Propane formula = C₃H₈

Oxygen formula = O₂

Carbon dioxide formula = CO₂

Water formula = H₂O

<u>Reaction:</u>

                         C₃H₈  +   5O₂   ⇒    3CO₂   +   4H₂O

                  Reactants            Elements     Products

                          3                          C                    3

                          8                          H                    8

                         10                         O                   10

6 0
3 years ago
If you forget your units , is disaster guaranteed
Vera_Pavlovna [14]
In chemistry, yes...yes it is.
4 0
4 years ago
Read 2 more answers
True or False? You should change the subscripts to balance chemical equations.
Kitty [74]
False subscripts cannot be changed to balance chemical equations
3 0
3 years ago
How many moles are in 35.5 g of aluminum?
Blizzard [7]

Answer:

1.316 moles of Aluminum

Explanation:

The molar mass for Al is 26.98 g/mol

\frac{35.5g}{26.98g/mol} =1.316 moles Al

3 0
3 years ago
Under what pressure will a scientist need to store 0.400 miles of gas if the container has a volume of 200.0 mL and the temperat
mihalych1998 [28]
Hello!

Ok so for this problem we use the ideal gas law of PV=nRT and I take it that the scientist needs to store 0.400 moles of gas and not miles.

So if we have
n=0.400mol
V=0.200L
T= 23degC= 273k+23c=296k
R=ideal gas constant= 0.0821 L*atm/mol*k

So now we rearrange equation for pressure(P)

P=nRT/V
P=((0.400mol)*(0.0821 L*atm/mol*k)*(296k))/(0.200L) = 48.6 atm of pressure

Hope this helps you understand the concept and how to solve yourself in the future!! Any questions, please feel free to ask!! Thank you kindly!!!
4 0
3 years ago
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