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kenny6666 [7]
3 years ago
15

F. You get inside and you have to push the cart across a thick carpet. Describe

Physics
1 answer:
aev [14]3 years ago
5 0

Answer:

Forces Due to Friction and Newton's Third Law

The forces on the cart include the forward force the horse exerts on the cart and the backward force due to friction at the ground, acting on the wheels. At rest, or at constant velocity, these two are equal in size, because the acceleration of the cart is zero.

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A guy wire 1034 feet long is attached to the top of a tower. When pulled taut, it touches level ground 699 feet from the base of
kolezko [41]

Answer:

80.386 degrees

Explanation:

We use the cosine equation here (which is the adjacent side of the unknown angle divided by the hypotenuse

The adjacent side = 699ft

The hypotenuse = 1034ft

using cos∅ = Adjacent/hypotenuse

where ∅ is the unknown angle

cos ∅ = 699/1034 = 0.167

∅ = arccos 0.167 = 80.368°

As easy as one can imagine

8 0
3 years ago
What happens when you boil seawater(no copying)
geniusboy [140]

Answer:

The water turns in to vapor and rises in the air leaving the salt  behind

Explanation:

8 0
3 years ago
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Does a wall or door have more inertia?
suter [353]

Answer:

wall

Explanation:

4 0
3 years ago
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What are the coordinates of the point that is 1/5 of the way from A(-7,-4) to B(3, 6)?
Olegator [25]

Answer:

coordinate will be

r = (1.33,4.33)

Explanation:

As we know that if a point will divide two given coordinates in m : n ratio

then in that case the point is given as

x = \frac{mx_1 + nx_2}{m+n}

y = \frac{my_1 + ny_2}{m+n}

here we know that two points are

(-7, -4) and (3, 6)

and the ratio is given as 1 : 5

now from above formula we will have

x = \frac{1(-7) + 5(3)}{1 + 5} = 1.33

y = \frac{1(-4) + 5(6)}{1 + 5} = 4.33

so coordinate will be

r = (1.33, 4.33)

7 0
3 years ago
A parallel beam of light of wavelength 4.5 x 10^-7 m is incident on a pair of slits that are 5.0 x 10^-4 m apart. The interferen
RSB [31]

Answer:

1.8x10⁻³m

Explanation:

From the question above, the following information was used to solve the problem.

wavelength λ = 4.5x10⁻⁷m

Length L = 2.0 meters

distance d = 5 x 10₋⁴m

ΔY = λL/d

= 4.5x10⁻⁷m (2) / 5 x 10₋⁴m

= 0.00000045 / 0.0005

= 0.0000009/0.0005

= 0.0018

= 1.8x10⁻³m

from the solution above The separation between two adjacent bright fringes is most nearly 1.8x10⁻³m

thank you!

3 0
3 years ago
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