Answer:
a. H=(1/2)*a*t^2
B.h=16.09ft
C.t= 1.22s
Explanation:
Explanation: Newton's equation of motion. This is called motion under free fall.
S=ut +(1/2)*a*t^2
Let S=H, and a=g
1.
H=ut +(1/2)*g*t^2
H=distance covered in ft(24ft)
u= initial velocity (ft/s)
t= time covered in seconds
g=acceleration due to gravity(ft/s^2)
a=g (32.185ft/s)
When u=0
H=(1/2)*g*t^2
2. H=(1/2)*g*t^2
g=32.185ft/s^2
t=1s
Juxtaposing the values into the equation
H= (1/2)* 32.185*(1)^2
H=16.09ft
3. When the maximum distance covered is 24ft, then using
H=(1/2)*a*t^2
24=0.5*32.165*t^2
24=16.09t^2
1.491=t^2
Find the square root of both sides
t=1.22s
It takes 1.22s to hit the ground
