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True [87]
3 years ago
13

A cyclist moves at 10 m / s for 5 minutes and at 18 m / s for 6 minutes in the same direction and direction. Get the average spe

ed of this movement.
A.14.4 m/s
B.2.5 m/s
C.25.0 m/s
D.31.6 m/s
E.None of the above
Physics
1 answer:
andre [41]3 years ago
7 0

total speed/total time=28/11=approx 2.8, just under.

makes it b, surprisingly

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Train cars are coupled together by being bumped into one another. Suppose two loaded train cars are moving toward one another, t
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Answer:

0.13 m/s

Explanation:

m_1 = Mass of first car = 140000 kg

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u_1 = Initial Velocity of first car = 0.3 m/s

u_2 = Initial Velocity of second car = -0.12 m/s

v = Velocity of combined mass

For elastic collision

m_1u_1 + m_2u_2 =(m_1 + m_2)v\\\Rightarrow v=\frac{m_1u_1 + m_2u_2}{m_1 + m_2}\\\Rightarrow  v=\frac{140000\times 0.3 + 95000\times -0.12}{140000+ 95000}\\\Rightarrow v=0.13\ m/s

Their final velocity is 0.13 m/s

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3 years ago
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A parachute on a drag race car opens and changes the velocity of the car from 75 m/s to 45 m/s in 8 seconds. Calculate the avera
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Answer:

friction, conduction and induction

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3 years ago
A student throws a set of keys vertically upward to her sorority sister, who is in a window 3.50 m above. The second student cat
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Answer:

a) 8.58 m/s upward

b) -2.211 m/s downward

Explanation:

Let gravitational acceleration g = -9.81m/s2. This is negative because it deceleration the upward motion of the key.

(a)We have the following equation of motion

s = v_0t + gt^2/2

where v_0 is the initial upward velocity of the keys, t = 1.1s is the time it takes for the keys to travel a distance of s = 3.5 m

3.5 = v_01.1 - 9.81*1.1^2/2

3.5 = 1.1v_0 - 5.94

1.1v_0 = 3.5 + 5.94 = 9.44

v_0 = 9.44 / 1.1 = 8.58 m/s

So the keys were thrown initially upward with a speed of 8.58 m/s

(b) If the initial velocity of the key is 8.58 m/s and it is subjected to a deceleration of 9.81m/s2 for 1.1s then the velocity right at the 1.1s instant is

v = v_0 + gt = 8.58 - 9.81*1.1 = -2.211 m/s

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