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andriy [413]
3 years ago
12

The pressure of liquid varies as per it's depth.

Physics
1 answer:
irga5000 [103]3 years ago
6 0

Answer: The pressure in a liquid is different at different depths. Pressure increases as the depth increases. The pressure in a liquid is due to the weight of the column of water above. The greater pressure at the bottom would give a greater 'force per unit area' on the wall.

Explanation:

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Block B has mass 6.00 kg and sits at rest on a horizontal, frictionless surface. Block A has mass 2.50 kg and sits at rest on to
zzz [600]

Answer:

Explanation:

Block A sits on block B and force is applied on block A . Block A will experience two forces 1) force P and 2 )  friction force in opposite direction of motion . Block B will experience one force that is force of friction in the direction of motion .

Let force on block A be P . friction force on it will be equal to kinetic friction, that is μ mg , where μ is coefficient of friction and m is mass of block A

friction force = .4 x 2.5 x 9.8

= 9.8 N

net force on block A = P - 9.8

acceleration = ( P - 9.8 ) / 2.5

force on block B = 9.8

acceleration = force / mass

= 9.8 / 6

for common acceleration

( P - 9.8 ) / 2.5  = 9.8 / 6

( P - 9.8 ) / 2.5 = 1.63333

P = 13.88 N .

4 0
4 years ago
A small rubber wheel is used to drive a large pottery wheel. The two wheels are mounted so that their circular edges touch. The
Goshia [24]

Answer:

0.629\ \text{rad/s}^2 counterclockwise

9.98\ \text{s}

Explanation:

r_1 = Small drive wheel radius = 2.2 cm

\alpha_1 = Angular acceleration of the small drive wheel = 8\ \text{rad/s}^2

r_2 = Radius of pottery wheel = 28 cm

\alpha_2 = Angular acceleration of pottery wheel

As the linear acceleration of the system is conserved we have

r_1\alpha_1=r_2\alpha_2\\\Rightarrow \alpha_2=\dfrac{r_1\alpha_1}{r_2}\\\Rightarrow \alpha_2=\dfrac{2.2\times 8}{28}\\\Rightarrow \alpha_2=0.629\ \text{rad/s}^2

The angular acceleration of the pottery wheel is 0.629\ \text{rad/s}^2.

The rubber drive wheel is rotating in clockwise direction so the pottery wheel will rotate counterclockwise.

\omega_i = Initial angular velocity = 0

\omega_f = Final angular velocity = 60\ \text{rpm}\times \dfrac{2\pi}{60}=6.28\ \text{rad/s}

t = Time taken

From the kinematic equations of linear motion we have

\omega_f=\omega_i+\alpha_2t\\\Rightarrow t=\dfrac{\omega_f-\omega_i}{\alpha_2}\\\Rightarrow t=\dfrac{6.28-0}{0.629}\\\Rightarrow t=9.98\ \text{s}

The time it takes the pottery wheel to reach the required speed is 9.98\ \text{s}

4 0
3 years ago
Predict the date of the next full moon.
lapo4ka [179]

Answer:

The 19th

Explanation:

going based off of the calandar, you just start from the 4 at the bottom and then just count up as you go through it agains starting back at the top.

4 0
3 years ago
Read 2 more answers
Which body is in equilibrium?
zloy xaker [14]

Which body is in equilibrium?

(1) a satellite orbiting Earth in a circular orbit .  No.  The forces on it are unbalanced.  There's only one force acting on it ... the force of gravity, pulling it toward the center of the Earth.  That's a centripetal force, and the satellite is experiencing centripetal acceleration.

(2) a ball falling freely toward the surface of Earth.  No.  The forces on it are unbalanced.  There's only one force acting on it ... the force of gravity, pulling it toward the center of the Earth.  The ball is accelerating toward the ground.  

<em> (3) a car moving with a constant speed along a  straight, level road.  YES.</em> We don't even need to analyze the forces, just look at the car.  It's moving in a straight line, and its speed is not changing.  The car's acceleration is zero !  That  right there tells us that the NET force ... the sum of all forces acting on the car ... is zero.  THAT's called 'equilibrium'.

(4) a projectile at the highest point in its trajectory.  No.  The forces on it are unbalanced.  There's only one force acting on it ... the force of gravity, pulling it toward the center of the Earth.  The projectile is accelerating toward the ground.

7 0
3 years ago
A sports car skids off of a wet mountain road at 48.5 m/s and lands in the river, 110
Oxana [17]

Answer:

  about 4.74 seconds

Explanation:

The time to fall distance d from height h is given by ...

  t = √(2d/g)

  t = √(2·110 m/(9.8 m/s^2)) ≈ 4.74 s

It will take the car about 4.74 seconds to fall 110 meters to the river.

__

We assume the car's speed is horizontal, so does not add or subtract anything to/from the time to fall from the height.

3 0
3 years ago
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