The coordinates of the endpoints of line segments T'V' are; T'(-1, 2) and V'(0, 1).
<h3>What are the coordinates of the endpoints of the segment T'V'?</h3>
It follows from the task content that the transformation involved in the formation of the image from the pre-image is dilation by a scale factor of 1/4.
On this note, given that the coordinates of T and V from the task content are; (-4, 8) and (0,4), it follows that the coordinates of the endpoints as required are; T'(-1, 2) and V'(0, 1).
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Answer:
V = 672; SA = 544; LA = 448
Step-by-step explanation:
Answer:
y = -x - 1
Step-by-step explanation:
1. The slope-intercept form of any linear equation is y = mx + b, where y = y-coordinate, m = slope, x = x-coordinate, and b = y-intercept.
2. To find the slope given two points, we can use the formula 
and plug in the corresponding variable.
3. Okay, so the slope is -1x or just -x. This means that the equation looks like this so far: y = -x + b
4. To find b, the y-intercept, we can take the equation of 
and plug in the values!
5. Now that we have our y-intercept and slope, let's plug in those values and find the equation!
Therefore, the equation of the line is y = -x - 1. I hope this helped you!
Answer:
3.33lbs. repeating?
Step-by-step explanation:
I think it would just be 10/3 and be 3.33333333 and so on. (im just taking a guess)
Answer: A
Step-by-step explanation:493.88/5
