Question

A stone is launched at an angle of 50 degree with initial velocity of 22m/s. Find out its initial and final velocity.​

Answer 1

(a) The initial vertical velocity of the stone is 16.85 m/s and the initial horizontal velocity is 14.14 m/s.

(b) The final vertical velocity is 0 and the final horizontal velocity is 14.14 m/s.

Initial vertical velocity

The initial vertical velocity of the stone is calculated as follows;

Vi = Vsinθ

Vi = 22 x sin(50)

Vi = 16.85 m/s

Initial horizontal velocity

Vxi = V cosθ

Vxi = 22 x cos(50)

Vxi = 14.14 m/s

Final vertical velocity of the stone

Vf = Vi - gt

where;

• Vf is the final vertical velocity = 0 at maximum height

Final horizontal velocity of the stone

Vfx = Vxi = 14.14 m/s

Thus, the initial vertical velocity of the stone is 16.85 m/s and the initial horizontal velocity is 14.14 m/s.

The final vertical velocity is 0 and the final horizontal velocity is 14.14 m/s.

Learn more about vertical velocity here: brainly.com/question/24949996

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