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3 years ago

Find A and B I need help like asap so pleasee help

Physics

1 answer:

zloy xaker [14]3 years ago

8 0

Answer:

I don't understand?

Explanation:

Could you please elaborate?

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Sound travels faster through rigid material like steel rather than through spongy materials like rubber. Why?

drek231 [11]

<span>since sound travels using mechanical waves and needs a material medium to propagate and since mechanical waves spread through vibrations ...and since hard materials have their atoms packed closely....they need to vibrate with a smaller amplitude to pass on the wave....thus sound travels faster in a denser medium than a less dense one.</span>

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3 years ago

A person run 21.0 km west then runs 10.0 km east what is the persons distance

VashaNatasha [74]

Answer:

31.0 km

Explanation:

21.0+10.0=31.0 km

6 0

3 years ago

Read 2 more answers

N LC circuit has an oscillation frequency of 105 Hz. If C = 0.1 F , then L must be about:

Umnica [9.8K]

Answer:

L = 22.97 H

Explanation:

Given that,

Capacitance, $C=0.1\ \mu F=0.1\times 10^{-6}\ F$

Oscillation frequency, f = 0.5 Hz

The frequency of an AC circuit is given by :

$f=\dfrac{1}{2\pi \sqrt{LC} }$

Where

L is impedance

$f^2=\dfrac{1}{4\pi ^2LC}\\\\L=\dfrac{1}{4\pi ^2 f^2 C}\\\\\text{Putting all the values}\\\\L=\dfrac{1}{4\pi^2 \times (105)^2\times 0.1\times 10^{-6}}\\\\L=22.97\ H$

So, the impedance of LC circuit 22.97 H.

7 0

2 years ago

A torsional pendulum consists of a disk of mass 450 g and radius 3.5 cm, hanging from a wire. If the disk is given an initial an

Montano1993 [528]

To solve this problem we will use the kinematic equations of angular motion, starting from the definition of angular velocity in terms of frequency, to verify the angular displacement and its respective derivative, let's start:

$\omega = 2\pi f$

$\omega = 2\pi (2.5)$

$\omega = 5\pi rad/s$

The angular displacement is given as the form:

$\theta (t) = \theta_0 cos(\omega t)$

In the equlibrium we have to $t=0, \theta(t) = \theta_0$ and in the given position we have to

$\theta(t) = \theta_0 cos(5\pi t)$

Derived the expression we will have the equivalent to angular velocity

$\frac{d\theta}{dt} = 2.7rad/s$

Replacing,

$\theta_0(sin(5\pi t))5\pi = 2.7$

Finally

$\theta_0 = \frac{2.7}{5\pi}rad = 9.848\°$

Therefore the maximum angular displacement is 9.848°

6 0

3 years ago

What is the force that the gas exerts on each of the six sides of the box when the gas temperature is 20.0∘C?

Taya2010 [7]

Incomplete question as number of moles and length is missing.So I have assumed 3 moles and length of 0.300 m.So the complete question is here:

Three moles of an ideal gas are in a rigid cubical box with sides of length 0.300 m.What is the force that the gas exerts on each of the six sides of the box when the gas temperature is 20.0∘C?

Answer:

The Force act on each side is 2.43×10⁴N

Explanation:

Given data

n=3 mol

L=0.3 m

Temperature=20.0°C=293 K

To find

Force F

Solution

To get force act on each side it would employ by

F=P.A

Where P is pressure

A is Area

First we need to find pressure by applying ideal gas law

$P.V=nRT\\P=\frac{nRT}{V}\\ P=\frac{(3mol)(8.315J/mol)(293K)}{(0.3m*0.3m*0.3m)}\\P=27.069*10^{4}Pa$

So The Force is given as:

$F=P.A\\F=(27.069*10^{4} )(0.3m*0.3m)\\F=2.43*10^{4}N$

The Force act on each side is 2.43×10⁴N

3 0

3 years ago