Snell's law is defined as “The ratio of the sine of the angle of incidence to the sine of the angle of refraction is a constant, for the light of a given colour and for the given pair of media”.
Angle of incidence is the angle when the light strikes an object while angle of reflection is the angle produced when the light strikes off/reflects from the object.
The relation between these two is that both the angles are equal.
The law of reflection states that when a ray of light reflects off a surface, the angle of incidence is equal to the angle of reflection.
Hope this helps!
It will be approximately equal.
<h3>How will the final kinetic energy change?</h3>
We can infer that all of the energy in the electron is Potential energy (PE) because the energy provided by the photon is hardly enough to outweigh the work function.
It will gain kinetic energy (KE) as it advances in the direction of the anode because it is moving through an electric field. All of the PE will have been transformed to KE by the time it reaches the anode.
According to the question
K = hf - W
W = Work function
The energy of photons is comparable. After conversion, there was only a little amount of KE remaining.
Therefore, PE (W) essentially equals KE (K).
It will about be equal.
Learn more about work function here:
brainly.com/question/19595244
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<u>If the disk turns with constant angular velocity, the following statements about it are true
</u>
- The linear acceleration of Q is twice as great as the linear acceleration of P
- is moving twice Q as fast as P.
Answer: Options D and E
<u>Explanation:
</u>
Let us consider that R is the radius of the circular disc. So as Q is on the rim, so the distance of Q from the centre of the disc is R and as P is the midpoint between centre and rim of the disk, so the distance of P from the centre is R/2.
As we know that the angular velocity of the circular disk will be equal to the ratio of distance covered by that point to the time taken. So the angular velocity at point Q will be
As R is the distance of point Q from the centre of the disc.
Similarly
,
So if we equate v with v’ we obtain that
Therefore, the point Q will be moving twice as fast as P. As the velocity of Q is more than O, the linear acceleration of point Q will also be twice as great as the linear acceleration of P.
This is because acceleration is directly proportional to the rate of change in velocity. So if velocity increases in the factor of 2, the acceleration of point Q will also increase twice with respect to point P.
Answer:
t = 20s
Explanation:
In order for the police car to capture the other car, both cars must travel the same length.
The distance traveled by the first vehicle is:
S = ^ Vt = 40t, where t represents the elapsed time and V the vehicle speed.
The distance traveled by the police car is:
S = at ^ 2/2 = 2t ^ 2, where t represents the elapsed time, a is the acceleration of the car.
As the distances traveled are equal:
40t = 2t ^ 2 in this way t = 20s
