According to Newton's second law
E.e = a * mp ..... (1)
where
E is the magnitude of the electric field; e = 1.6 * 10^-19 is the elementary charge; mp = 1.67*10^-27 kg is the proton mass; a is the acceleration.
So, the distance
l = at^2/2 .......(2)
The proton accelerated
a = 2l / t^2 ...........(3)
From equations (1) and (3)
E= 32.51 V/m
Electric field
The physical field that surrounds electrically charged particles and exerts a force on all other charged particles in the field, either attracting or repelling them, is known as an electric field (also known as an E-field). It can also refer to a system of charged particles' physical field. Electric charges and time-varying electric currents are the building blocks of electric fields. The electromagnetic field, one of the four fundamental interactions (also known as forces) of nature, manifests itself in both electric and magnetic fields.
To learn more about an electric field refer here:
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Missing question: "What is the spring's constant?"
Solution:
The object of mass m=6.89 kg exerts a force on the spring equal to its weight:

When the object is attached to the spring, the displacement of the spring with respect to its equilibrium position is

And by using Hook's law, we can find the constant of the spring:
Answer:
C. The bug's change in momentum is equal to the car's change in momentum.
Explanation:
As we know by Newton's 2nd law

here we have also know that when car hits the bug then force applied by wind shield on the bug is same as the force applied by the bug on the car's wind shield as per Newton's III law

so we know that

so we have

so correct answer will be
C. The bug's change in momentum is equal to the car's change in momentum.
The answer would be slowly
Answer:
c.Law
Explanation:
i think you must learn and write however good luck