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Yanka [14]
3 years ago
8

EASY!!!!!!!!!- Why is Spacex's rockets better than normal rockets? Give 6 points

Engineering
2 answers:
kozerog [31]3 years ago
6 0

Answer:

What makes spacex rockets so special?

First privately funded fully liquid-fueled rocket to reach orbit. First privately developed liquid-fueled rocket to put a commercial satellite in orbit. First private company to successfully launch, orbit, and recover a spacecraft. First private company to send a spacecraft to the International Space Station (ISS).

Explanation:

Unmatched Performance. With more than 5 million pounds of thrust at liftoff, Falcon Heavy is the most capable rocket flying. By comparison, the liftoff thrust of the Falcon Heavy equals approximately eighteen 747 aircraft at full power.

Eduardwww [97]3 years ago
4 0

Answer:

its a space rocket not a normal one .so if the normal ones can be destroyed this can not

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Steam at 75 kPa and 8 percent quality is contained in a spring-loaded piston–cylinder device, as shown in Figure, with an initia
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The heat transferred to and the work produced by the steam during this process  is 13781.618 kJ/kg

<h3>​How to calcultae the heat?</h3>

The Net Change in Enthalpy will be:

= m ( h2 - h1 ) = 11.216 ( 1755.405 - 566.78 ) = 13331.618 kJ/kg

Work Done (Area Under PV curve) = 1/2 x (P1 + P2) x ( V1 - V2)

= 1/2 x ( 75 + 225) x (5 - 2)

W = 450 KJ

From the First Law of Thermodynamics, Q = U + W

So, Heat Transfer = Change in Internal Energy + Work Done

= 13331.618 + 450

Q = 13781.618 kJ/kg

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What is Elon Musk mad about?
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What do Engineers aim to do
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How high a building could fire hoses effectively spray from the ground? Fire hose pressures are around 1 MPa. (It is also said t
Mrac [35]

Answer:

z_{2} = 91.640\,m

Explanation:

The phenomenon can be modelled after the Bernoulli's Principle, in which the sum of heads related to pressure and kinetic energy on ground level is equal to the head related to gravity.

\frac{P_{1}}{\rho\cdot g} + \frac{v_{1}^{2}}{2\cdot g}= z_{2}+\frac{P_{2}}{\rho\cdot g}

The velocity of water delivered by the fire hose is:

v_{1} = \frac{(300\,\frac{gal}{min} )\cdot(\frac{3.785\times 10^{-3}\,m^{3}}{1\,gal} )\cdot(\frac{1\,min}{60\,s} )}{\frac{\pi}{4}\cdot (0.3\,m)^{2}}

v_{1} = 0.267\,\frac{m}{s}

The maximum height is cleared in the Bernoulli's equation:

z_{2}= \frac{P_{1}-P_{2}}{\rho\cdot g} + \frac{v_{1}^{2}}{2\cdot g}

z_{2}= \frac{1\times 10^{6}\,Pa-101.325\times 10^{3}\,Pa}{(1000\,\frac{kg}{m^{3}} )\cdot(9.807\,\frac{m}{s^{2}} )} + \frac{(0.267\,\frac{m}{s} )^{2}}{2\cdot (9.807\,\frac{m}{s^{2}} )}

z_{2} = 91.640\,m

7 0
3 years ago
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