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vazorg [7]
3 years ago
7

What is the maximum amount of ammonia that can be produced when 0.35 mol Nz reacts with 0.90 mol Hz?

Chemistry
1 answer:
professor190 [17]3 years ago
5 0

Answer:

0.6 moles NH₃

Explanation:

The reaction that takes place is:

  • N₂ + 3H₂ → 2NH₃

First we <u>determine the limiting reactant</u>:

  • 0.35 mol N₂ would react completely with (3*0.35) 1.05 moles of H₂. There are not as many H₂ moles, so H₂ is the limiting reactant.

Then we <u>convert H₂ moles (the limiting reactant) to NH₃ moles</u>, keeping in mind the <em>stoichiometry of the reaction</em>:

  • 0.90 mol H₂ * \frac{2molNH_3}{3molH_2}= 0.6 moles NH₃

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