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2 years ago

Domain and, range in interval notation

Mathematics

1 answer:

Bas_tet [7]2 years ago

4 0

Domain: [-4,4] (left-to-right or x-values used)

Range: [-4,4] (down-to-up or y-values used)

Function: no

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Which linear function represents the table? A) y = 2x − 5 B) y = 2x + 5 C) y = −2x + 5 D) y = −2x − 5

lubasha [3.4K]

Answer:

y= -2x - 1

Step-by-step explanation:

that is the answer sorry if wrong

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3 years ago

Each of 8 samples has a different standard deviation. How many of the 8 samples could be from the same population?

Oduvanchick [21]

What are the choices? Like A<B<C<D?

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3 years ago

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Please answer one question asap A(-4,3) B(2,-1) D(-4,-1) C(2,-5)

Leni [432]

Answer:

Step-by-step explanation:

Vertices of the given quadrilateral are A(-4, 3), B(2, -1), C(2, -5) and D(-4, -1)

Since, slope of a line passing through two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by,

Slope = $\frac{y_2-y_1}{x_2-x_1}$

Slope of AB = $\frac{3+1}{-4-2}$

= $-\frac{2}{3}$

Slope of AD = $\frac{3+1}{-4+4}$

= Not defined (Parallel to y-axis)

Slope of DC = $\frac{-5+1}{2+4}$

= $-\frac{2}{3}$

Slope of BC = $\frac{-1+5}{2-2}$

= Not defined (Parallel to y-axis)

Slope of AB = slope of DC = $-\frac{2}{3}$

Slope of BC = slope of AD = Not defined (parallel to y-axis)

As per property of a parallelogram,

"Opposite sides of a parallelogram are parallel and equal in measure"

Therefore, ABCD is a parallelogram.

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3 years ago

A police cruiser is traveling at 20.0 m/s when the officer spies a speeder. The cruiser accelerates at 3.0 m/s^2 for 5.0 seconds

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For the first 5.0 seconds, the cruiser covers a distance of

$\left(20.0\dfrac{\rm m}{\rm s}\right)(5.0\,\mathrm s)+\dfrac12\left(3.0\dfrac{\rm m}{\mathrm s^2}\right)(5.0\,\mathrm s)^2=137.5\,\mathrm m$

At this point, the cruiser will have achieved a velocity of

$\left(20.0\dfrac{\rm m}{\rm s}\right)+\left(3.0\dfrac{\rm m}{\mathrm s^2}\right)(5.0\,\mathrm s)=35\dfrac{\rm m}{\rm s}$

The cruiser will take

$\left(35\dfrac{\rm m}{\rm s}\right)-\left(5.0\dfrac{\rm m}{\mathrm s^2}\right)t=0\implies t=7.0\,\mathrm s$

to come to a stop as it decelerates. It will have covered a total distance of

$(137.5\,\mathrm m)+\left(35\dfrac{\rm m}{\rm s}\right)(7.0\,\mathrm s)+\dfrac12\left(-5.0\dfrac{\rm m}{\mathrm s^2}\right)(7.0\,\mathrm s)^2=\boxed{260\,\mathrm m}$

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2 years ago

What is the m2ABC? a) m ABC = 15° b) m2ABC = 45° c) MLABC = 60° d) MZABC = 75°

WITCHER [35]

Answer:

m∠ABC = 60°

Step-by-step explanation:

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3 years ago