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antiseptic1488 [7]
2 years ago
7

If the period of a pendulum were 2.4 s on the moon, which has an acceleration due to gravity of 1.67 m/s^2, then how long would

the rope be?
If a grasshopper can jump at 15 m/s at a 37° angle above horizontal, then how far can it Jump?

Please help asap!
Physics
1 answer:
guajiro [1.7K]2 years ago
5 0
<h2>Reffer the attachment </h2>

Mark as brainlist ❤️❤️

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When a falling body is at distance above the surface which is 4 times the Earth radius what is the acceleration due to Earth gra
Hoochie [10]

Answer:

Explanation:

g = GM/R²

as gravity decreases by the inverse of the square of the distance, increasing the distance by 4 times will reduce gravity to 1/16 that at the surface

9.8 / 16 = 0.61 m/s²

8 0
3 years ago
Which of the following is true for a parallel circuit?
svet-max [94.6K]

Answer:

  1. Will you show the some answers so I can help
3 0
2 years ago
What is your displacement if you travel 5 miles north to the store
kumpel [21]

Answer:

5miles North

Explanation:

The displacement to the store is 5miles northward.

Displacement is the distance traveled in a specific direction. Displacement is a vector quantity.

A vector has both magnitude and direction.

The magnitude is the amount of that quantity

The direction is its orientation from a reference.

 Therefore, the displacement is 5miles north

3 0
2 years ago
93 cm3 liquid has a mass of 77 g. When calculating its density what is the appropriate number of significant figures
lubasha [3.4K]

Answer:

828 kg/m³ or 0.828 g/cm³

Explanation:

Applying,

D = m/V............. Equation 1

Where D = density of the liquid, m = mass of the liquid, V = volume of the liquid.

From the question,

Given: m = 77 g , V = 93 cm³

Substitute these values into equation 1

D = 77/93

D = 0.828 g/cm³

Converting to kg/m³

D = 828 kg/m³

6 0
3 years ago
A car accelerates at 3 m/s*2. Assuming the car starts from rest, how much time does it need to
uranmaximum [27]
<h3><u>Given</u><u>:</u><u>-</u></h3>

Acceleration,a = 3 m/s²

Initial velocity,u = 0 m/s

Final velocity,v = 12 m/s

<h3><u>To</u><u> </u><u>be</u><u> </u><u>calculated:-</u><u> </u></h3>

Calculate the time take by a car.

<h3><u>Solution:-</u><u> </u></h3>

According to the first equation of motion:

v = u + at

★ Substituting the values in the above formula,we get:

⇒ 12 = 0 + 3 × t

⇒ 12 = 3t

⇒ 3t = 12

⇒ t = 12/3

⇒ t = 4 sec

5 0
3 years ago
Read 2 more answers
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