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Lera25 [3.4K]
2 years ago
10

In comparing two distributions, which attribute would you not compare?

Mathematics
1 answer:
krok68 [10]2 years ago
3 0
A. Joint frequency, it’s right I checked it myself
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Multiply and Simplify. 4x+4/x^2 × (x+2)(x-1)/x+1
NARA [144]

Answer:


Step-by-step explanation:

(x^2 - 4)(x^2 - 4)

Simplifying

(x2 + -4)(x2 + -4)

Reorder the terms:

(-4 + x2)(x2 + -4)

Reorder the terms:

(-4 + x2)(-4 + x2)

Multiply (-4 + x2) * (-4 + x2)

(-4(-4 + x2) + x2(-4 + x2))

((-4 * -4 + x2 * -4) + x2(-4 + x2))

((16 + -4x2) + x2(-4 + x2))

(16 + -4x2 + (-4 * x2 + x2 * x2))

(16 + -4x2 + (-4x2 + x4))

Combine like terms: -4x2 + -4x2 = -8x2

(16 + -8x2 + x4)

5 0
3 years ago
100
disa [49]

Answer:

Distance of ladder top from ground = 9.2 meter (Approx.)

Step-by-step explanation:

Given:

Angle of elevation between ground and ladder = 43°

Length of ladder = 13.5 meter

Find:

Distance of ladder top from ground

Computation:

Length of ladder = Hypotenuse

Distance of ladder top from ground = Perpendicular

Sinθ = Perpendicular / Hypotenuse

Sin 43 = Distance of ladder top from ground / Length of ladder

0.6819 = Distance of ladder top from ground / 13.5

Distance of ladder top from ground = 9.20565

Distance of ladder top from ground = 9.2 meter (Approx.)

8 0
3 years ago
Slope = -5 and Y -intercept (0,7)
ruslelena [56]
Your answer will be Slope m=-4/5
8 0
3 years ago
Please help I'll mark brainliest​
zhenek [66]

✿————✦————✿————✦————✿————✦————✿

So, to find the mean they added up the scores from 20 seasons and divided by 20, the number of seasons to get an average score of 10.4.

10.4 = (x1 +x2 +x3 ... +x20 )/20

Then;

10.4*(20) = (x1 +x2 +x3 ... +x20 )

208 = sum of the first 20 seasons

We want to add one more number in there, the 21st season with a score of 14. Add the 14 to the sum of the first 20 seasons and then divide by 21, the new number of seasons you're averaging.

Mean = (208+14)/21  

✿————✦————✿————✦————✿————✦————✿

Answer

= 10.6

✿————✦————✿————✦————✿————✦————✿

#<em>carryonlearning</em>

5 0
2 years ago
The perimeters of similar triangles are in the same ratio as the corresponding sides.
Stella [2.4K]
Truth

ewidence
k - <span>scale similarities
a,b,c = </span>sides of the triangle
p - <span>perimeter of a triangle</span>
<span>
k*a + k*b + k*c = k(a+b+c) = k*p

</span>triangles
a = 3
b = 15
c = 14

triangles 1:2
2a = 2*3 = 6
2b = 2*15 = 30
2c = 2*14 = 28

<span>


</span>
5 0
3 years ago
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