The total length of the wire needed to make this shape is 162cm
<h3>Perimeter of a triangle</h3>
The perimeter of a triangle is the sum of the external side of the triangle.
Given the following parameters
Length of one side of the outside shape = 24cm
The side length of the smaller triangle = 24/4 = 6cm
The perimeter of the smallest triangle 3(6) = 18cm
The perimeter of the smaller triangle (at the middle) = 12(3) = 36cm
Total length of wire needed. = 3(24) + 3(18) + 36
Total length of wire needed = 72 + 54 + 36
Total length of wire needed = 162cm
Hence the total length of the wire needed to make this shape is 162cm
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Answer: The length is 20.
Step-by-step explanation:
If UW is the line segment, then the length of VW and UV has to equal to the length of UW
VW = 6
UV = 14
6 + 14 = 20
The answer or range would be 40
Step-by-step explanation:
Use SOH-CAH-TOA.
Sine = Opposite / Hypotenuse
Cosine = Adjacent / Hypotenuse
Tangent = Opposite / Adjacent
Let's start with #12. The hypotenuse is 18. The side adjacent to ∠B is 6. Since we have the adjacent side and hypotenuse, we should use cosine.
cos B = 6/18
Solving for B:
B = cos⁻¹(6/18)
Using a calculator:
B ≈ 70.5°
Now let's do #14. The side adjacent to ∠B is 19, and the side opposite of ∠B is 22. Since we have the adjacent side and opposite side, we should use tangent.
tan B = 22/19
Solving for B:
B = tan⁻¹(22/19)
Using a calculator:
B ≈ 49.2°
Answer:
-5
Step-by-step explanation:
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