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3 years ago

This is the graph of f(x) = lxl.

Mathematics

1 answer:

irina [24]3 years ago

5 0

Answer:

You are clicking on graphs.

However, you should sketch a graph of your function to see what the correct one looks like.

Create a table containing a few values of x and y

I chose x = -4, -2, 0, 2, 4.

Draw your axes

Plot your points

Draw the graph

Your graph should look like the one below.

Step-by-step explanation:

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Enrique estimates that his utilities will cost him $86.00 per month over the courses of the next 3 years. What is his total esti

Dafna1 [17]

Answer:

$3096

Step-by-step explanation:

There are 12 months in 1 year.

3 × 12 = 36

There are 36 months in 3 years.

$86 × 36 = $3096

4 0

2 years ago

Read 2 more answers

2+0=2 What property is illustrated? A. associative property of addition B. commutative property of addition C. identity property

valkas [14]

C. identity property of addition. hope it helps

7 0

4 years ago

Read 2 more answers

What is the solution of the equation x2 − 2x = −2?

RSB [31]

Answer:

-2

Step-by-step explanation:

6 0

3 years ago

Given the sequence -2,-8/3,-10/3,-4,-14/3 find the recursive formula

balu736 [363]

Step-by-step explanation:

-2, -8/3, -10/3, -4, -14/3

Write as multiples of 1/3.

-6/3, -8/3, -10/3, -12/3, -14/3

This is an arithmetic sequence where the first term is -6/3 and the common difference is -2/3.

Therefore, the recursive formula is:

aᵢ₊₁ = aᵢ − 2/3, a₁ = -2

3 0

3 years ago

Please help!! MathsWatch, Surd Expressions, Clip 207c

dexar [7]

Answer:

$A=(72+36\sqrt{3})\ mm^2$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

Let

a ----> the height of rectangle in mm

b ---> the base of rectangle in mm

step 1

Find the base of rectangle

$b=AB+BC+CD+DE$ ----> by segment addition postulate

substitute

$b=3+3+3+3=12\ mm$

step 2

Find the height of rectangle

$a=FB+CG+GH$ ---> by segment addition postulate

substitute the given values

$a=3+CG+3\\a=6+CG$

Find the length sides CG

Applying the Pythagorean Theorem

$BG^2=BC^2+CG^2$

substitute the given values

$6^2=3^2+CG^2$

$CG^2=6^2-3^2$

$CG=\sqrt{27}\ mm$

simplify

$CG=3\sqrt{3}\ mm$

therefore

$a=(6+3\sqrt{3})\ mm$

step 3

Find the area of rectangle

$A=ab$

we have

$a=(6+3\sqrt{3})\ mm$

$b=12\ mm$

substitute

$A=(6+3\sqrt{3})(12)=(72+36\sqrt{3})\ mm^2$

8 0

3 years ago