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nataly862011 [7]
3 years ago
15

Do Gas Laws apply to Liquids and why?

Chemistry
1 answer:
Sonbull [250]3 years ago
5 0

Gas Laws DO NOT apply to Liquids, because liquids have a definite volume. An important part of gas laws have to do with volume as a variable, which means it changes. This is true for gasses, but not for liquids.

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The component which dissolves in a solution is called the?
VladimirAG [237]

The correct answer is Solute

Explanation:

In chemistry, a solution refers to a homogenous mixture of two substances that occurs through dissolution, this means once they are mixed the substances form a uniform new substance and cannot be easily separated. Additionally, in chemistry, the substances involved in a solution are either classified as solutes if they are the substances that dissolve to form a solution or as solvents in the case of substances in which the solute dissolves in. For example, if you mix salt and water, the salt acts as the solute while the water is the solvent. Thus, the component which dissolves in a solution is called the solute.

5 0
3 years ago
Question 6 pls I need help this is due in 2 minutes!!..
MAVERICK [17]

Answer:

c

Explanation:

7 0
2 years ago
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the copper anode is weighed before and after the electrolysis reation. if the copper anode is not completely dry when it is weig
Dmitrij [34]

Answer:

Faraday's constant will be smaller than it is supposed to be.

Explanation:

If the copper anode was not completely dry when its mass was measured, mass of the copper must be heavier than it should have been. Hence, the calculated Faraday’s constant would be smaller than it is supposed to be since when calculating Faraday’s Constant, the charge transferred is divided by the moles of electrons.

5 0
3 years ago
A laboratory analysis of a sample finds it is composed of 38.8% carbon, 16.2% hydrogen, and 45.1% nitrogen. What is its empirica
Sladkaya [172]

Answer: The empirical formula for the given compound is CH_5N

Explanation : Given,

Percentage of C = 38.8 %

Percentage of H = 16.2 %

Percentage of N = 45.1 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of C = 38.8 g

Mass of H = 16.2 g

Mass of N = 45.4 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{38.8g}{12g/mole}=3.23moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{16.2g}{1g/mole}=16.2moles

Moles of Nitrogen = \frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{45.4g}{14g/mole}=3.24moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 3.23 moles.

For Carbon = \frac{3.23}{3.23}=1

For Hydrogen  = \frac{16.2}{3.23}=5.01\approx 5

For Oxygen  = \frac{3.24}{3.23}=1.00\approx 1

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : N = 1 : 5 : 1

Hence, the empirical formula for the given compound is C_1H_5N_1=CH_5N

3 0
3 years ago
Now consider the quantum theory of conduction. At low temperatures, with scattering by lattice vibrations (phonons) not yet impo
nydimaria [60]

Answer:

jhjhh

Explanation:

jhhjhjh

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3 years ago
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