The empirical formula is C₇H₆O₂.
Assume that you have 100 g of the compound.
Then you have 68.84 g C and 4.962 g H.
Mass of O = (100 – 68.84 – 4.962) g = 26.20 g O.
Now, we must convert these masses to moles and find their ratios.
From here on, I like to summarize the calculations in a table.
<u>Element</u> <u>Mass/g</u> <u>Moles</u> <u>Ratio</u> <u> ×2</u> <u>Integers</u>
C 68.84 5.732 3.501 7.001 7
H 4.962 4.923 3.006 6.012 6
O 26.20 1.638 1 2 2
The empirical formula is C₇H₆O₂.
Answer:
3.9 laps
Explanation:
Step 1: Given data
Length of the hamster track (L): 255 cm
Total distance to be run (D): 10 m
Step 2: Convert "D" to centimeters
We will use the relationship 1 m = 100 cm.
10 m × (100 cm/1 m) = 1.0 × 10³ cm
Step 3: Calculate the number of laps (n) that the hamster should run
We will use the following expression.
n = D/L
n = 1.0 × 10³ cm/255 cm
n = 3.9
Explanation:
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Answer:
Theoretical yield of hydrogen is 1.11 g
Explanation:
Balanced equation, 
As Mg remain present in excess therefore HCl is the limiting reagent.
According to balanced equation, 2 moles of HCl produce 1 mol of
.
Molar mass of HCl = 36.46 g/mol
So, 40.0 g of HCl =
of HCl = 1.10 moles of HCl
Hence, theoretically, number of moles of
are produced from 1.10 moles of HCl = 
Molar mass of
= 2.016 g/mol
So, theoretical yield of
= 
There are 680,000 microliters in 0.68 liters.