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2 years ago

(5 1/4) divieded by (-2 1/2)

Mathematics

2 answers:

Mazyrski [523]2 years ago

7 0

Answer:

-2.1

Step-by-step explanation:

AfilCa [17]2 years ago

5 0

Answer:

-50

Hope this helps

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What is the approximate volume of a cone with a height of 6 mm and radius of 18 mm?

notka56 [123]

Answer:

678.24mm³

Step-by-step explanation:

The volume of the cone is computed using the formula:

$V = \pi r^2\dfrac{h}{3}$

Where:

r = radius of the circular base

h = height of the cone

π = 3.14

We are given the following:

r = 6mm

h=18mm

π = 3.14

So now that we have that, we just fill in the formula:

$V = \pi r^2\dfrac{h}{3}\\\\V = (3.14)(6mm)^{2}\dfrac{18mm}{3}\\\\V= (3.14)(36mm^2)(6mm)\\\\V = (113.04mm^{2})(6mm)\\\\V=678.24mm^{3}$

6 0

3 years ago

Read 2 more answers

20x^2-19x+3 divided by 5x-1

BabaBlast [244]

(20x^2-19x+3)/5x-1
(400x-19x+3)/5x-1
(381x+3)/5x-1
381x/5x-1 + 3/5x-1
(381/5-381) + (3/5x -3)
(76.2-381) + (3/5x -3)
304.8 + 3/5x-3
101.8 +3/5x

That's what I got. I'm not too sure if it helps though.

3 0

3 years ago

Read 2 more answers

he mean incubation time of fertilized eggs is 23 days. Suppose the incubation times are approximately normally distributed with

algol [13]

I think a but I’m not quite sure

8 0

3 years ago

SOLUTION We observe that f '(x) = -1 / (1 + x2) and find the required series by integrating the power series for -1 / (1 + x2).

Ann [662]

Answer:

Required series is:

$\int{\frac{-1}{1+x^{2}} \, dx =-x+\frac{x^{3}}{3}-\frac{x^{5}}{5}+\frac{x^{7}}{7}+.....$

Step-by-step explanation:

Given that

$f'(x) = -\frac{1}{1 + x^{2}}$ ---(1)

We know that:

$\frac{d}{dx}(tan^{-1}x)=\frac{1}{1+x^{2}}$ ---(2)

Comparing (1) and (2)

$f'(x)=-(tan^{-1}x)$ ---- (3)

Using power series expansion for $tan^{-1}x$

$f'(x)=-tan^{-1}x=-\int {\frac{1}{1+x^{2}} \, dx$

$= -\int{ \sum\limits^{ \infty}_{n=0} (-1)^{n}x^{2n}} \, dx$

$= -\sum{ \int\limits^{ \infty}_{n=0} (-1)^{n}x^{2n}} \, dx$

$=-[c+\sum\limits^{ \infty}_{n=0} (-1)^{n}\frac{x^{2n+1}}{2n+1}]$

$=C+\sum\limits^{ \infty}_{n=0} (-1)^{n+1}\frac{x^{2n+1}}{2n+1}$

$=C-x+\frac{x^{3}}{3}-\frac{x^{5}}{5}+\frac{x^{7}}{7}+.....$

$tan^{-1}(0)=0 \implies C=0$

Hence,

$\int{\frac{-1}{1+x^{2}} \, dx =-x+\frac{x^{3}}{3}-\frac{x^{5}}{5}+\frac{x^{7}}{7}+.....$

7 0

3 years ago

Suns the value of m, rounded to the nearest tenth

german

Answer: I think is B or A

Step-by-step explanation:

7 0

3 years ago