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erik [133]
2 years ago
11

(5 1/4) divieded by (-2 1/2)

Mathematics
2 answers:
Mazyrski [523]2 years ago
7 0

Answer:

-2.1

Step-by-step explanation:

AfilCa [17]2 years ago
5 0

Answer:

-50

Hope this helps

You might be interested in
What is the number of pie multiplied by two
Amanda [17]
Pie goes on forever, so you round it to 3.14.           
3.14*2= 6.28
Hope that helped!
8 0
4 years ago
Read 2 more answers
Please help me with this question!!!
ZanzabumX [31]
What question are you talking about?
5 0
4 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B5x%2F8y%7D" id="TexFormula1" title="\sqrt[4]{5x/8y}" alt="\sqrt[4]{5x/8y}" al
Furkat [3]

Answer:  \frac{\sqrt[4]{10xy^3}}{2y}

where y is positive.

The 2y in the denominator is not inside the fourth root

==================================================

Work Shown:

\sqrt[4]{\frac{5x}{8y}}\\\\\\\sqrt[4]{\frac{5x*2y^3}{8y*2y^3}}\ \ \text{.... multiply top and bottom by } 2y^3\\\\\\\sqrt[4]{\frac{10xy^3}{16y^4}}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{16y^4}} \ \ \text{ ... break up the fourth root}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{(2y)^4}} \ \ \text{ ... rewrite } 16y^4 \text{ as } (2y)^4\\\\\\\frac{\sqrt[4]{10xy^3}}{2y} \ \ \text{... where y is positive}\\\\\\

The idea is to get something of the form a^4 in the denominator. In this case, a = 2y

To be able to reach the 16y^4, your teacher gave the hint to multiply top and bottom by 2y^3

For more examples, search out "rationalizing the denominator".

Keep in mind that \sqrt[4]{(2y)^4} = 2y only works if y isn't negative.

If y could be negative, then we'd have to say \sqrt[4]{(2y)^4} = |2y|. The absolute value bars ensure the result is never negative.

Furthermore, to avoid dividing by zero, we can't have y = 0. So all of this works as long as y > 0.

3 0
3 years ago
2. Kim is x years old. Jordan is 7 years older than Kim. Four times Jordan’s age is equal to 200.
Shkiper50 [21]
Kim is X 
Jordan= x+7
So J x 4=200

This means 4(x+7) = 200
x=43
43+7=50
50 x 4=200

so Kim is 43 and Jordan is 50.
4 0
3 years ago
Find the length of BC.<br><br><br><br>Explain how you got it, please!<br>Thanks!
Vinvika [58]

Answer:

BC = 30.73

Here,

\sf \frac{AB}{BQ}  = \frac{CD}{DQ}

so first solve for QD

\sf \hookrightarrow \frac{32}{15}  = \frac{19.2}{DQ}

\sf \hookrightarrow 32(DQ)}  =19.2(15)

\sf \hookrightarrow 32(DQ)}  =288

\sf \hookrightarrow DQ =9

  • Hence, QD = 9

Now! <u>using Pythagoras theorem,</u>

  • CD² + BD² = BC²
  • 19.2² + (9+15)² = BC²
  • BC = √368.64+576
  • BC = 30.73499634
  • BC = 30.73 ( rounded to nearest hundredth )
4 0
2 years ago
Read 2 more answers
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