1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
marissa [1.9K]
3 years ago
6

_________ is amount of “ground” an object moves from its starting point and __________ is how much “ground” and object covers in

total.
Question options:


Displacement, distance


Speed, displacement


Distance, displacement


Movement, distance
Physics
2 answers:
Kamila [148]3 years ago
8 0

The correct answer is C.

Papessa [141]3 years ago
5 0

I believe the question talks about displacement and distance. The difference of the two is that displacement is the linear distance or shortest distance drawn from the starting point until the final point while distance is the whole trip that is covered, so the answer is:

<span>Displacement, distance</span>

You might be interested in
Now imagine a person dragging a 50 kg box along the ground with a rope, as
ANTONII [103]

Answer:

The coefficient of static friction between the box and floor is, μ = 0.061

Explanation:

Given data,

The mass of the box, m = 50 kg

The force exerted by the person, F = 50 N

The time period of motion, t = 10 s

The frictional force acting on the box, f = 30 N

The normal force on the box, η = mg

                                                     = 50 x 9.8

                                                     = 490 N

The coefficient of friction,

                            μ = f/ η

                               = 30 / 490

                               = 0.061

Hence, the coefficient of static friction between the box and floor is, μ = 0.061

7 0
3 years ago
Each of two small non-conducting spheres is charged positively, the combined charge being 40 μC. When the two spheres are 50 cm
Phantasy [73]

Answer:

1.44 x 10⁻⁶ C

Explanation:

q_{1} = charge on one sphere

q_{2} = charge on other sphere

q = Total charge on the two spheres = 40 μC

q_{1}+ q_{2} = q

q_{1}+ q_{2} = 40 x 10⁻⁶

q_{1} = (40 x 10⁻⁶) - q_{2}                                   eq-1

r = distance between the two spheres = 50 cm = 0.50 m

F = magnitude of force between the two spheres = 2.0 N

Magnitude of force between the two spheres is given as

F = \frac{k q_{1} q_{2}}{r^{2}}

2.0 = \frac{(9\times 10^{9}) ((40\times 10^{-6}) - q_{2}) q_{2}}{0.50^{2}}

q_{2} = 1.44 x 10⁻⁶ C

7 0
3 years ago
In each case, lifting or pushing, why must you exert a force to move the object? Q1-2: How much more effort is required to lift
musickatia [10]

Answer:

  1. Newton's first law applies. An object at rest will stay that way until a force is applied.
  2. Any amount of effort can be applied to any amount of mass (in the ideal case). The question is not sufficiently specific.

Explanation:

A force is required to move an object because the object will stay at rest until a force is applied.

__

The effort required to lift or push two masses instead of one depends on the desired effect. For the same kinetic energy, no more effort is required. For the same momentum, half the effort is required for two masses. For the same velocity, double the effort is required.

4 0
2 years ago
Dua titik yang bermuatan listrik yang sama, mula-mula berjarak 5 cm dan saling tarik menarik dengan gaya 225 N. Agar kedua titik
Serggg [28]

Answer:

15 cm

Explanation:

Dari pertanyaan yang diberikan di atas, diperoleh data sebagai berikut:

Gaya 1 (F₁) = 225 N

Jarak terpisah 1 (d) = 5 cm

Gaya 2 (F₂) = 25 N

Jarak terpisah 2 (d₂) =?

Kita dapat memperoleh persamaan yang berkaitan dengan gaya dan jarak muatan dua titik dengan menggunakan rumus berikut:

F = Kq₁q₂ / d²

Perbanyak silang

Fd² = Kq₁q₂

Menjaga Kq₁q₂ konstan, kita memiliki:

F₁d₁² = F₂d₂²

Dengan rumus di atas maka diperoleh jarak sebagai berikut:

Gaya 1 (F₁) = 225 N

Jarak terpisah 1 (d) = 5 cm

Gaya 2 (F₂) = 25 N

Jarak terpisah 2 (d₂) =?

F₁d₁² = F₂d₂²

225 × 5² = 25 × d₂²

225 × 25 = 25 × d₂²

5625 = 25 × d₂²

Bagilah kedua sisinya dengan 25

d₂² = 5625/25

d₂² = 225

Hitung akar kuadrat dari kedua sisi

d₂ = √225

d₂ = 15 cm

Oleh karena itu, muatan dua titik harus berjarak 15 cm untuk memiliki gaya tarik 25 N

4 0
2 years ago
Мета: :
Ierofanga [76]
I can’t answer this
3 0
3 years ago
Other questions:
  • Two students make the following claims:
    9·1 answer
  • How is velocity different from speed? Velocity is based on distance. Velocity includes direction. Velocity can be an average or
    13·2 answers
  • Sarah moves her box in 3 minutes and does 14 J of work. John moves his box in the same amount of time using 12 J of work. Who is
    7·2 answers
  • To protect her new two-wheeler, Iroda Bike
    7·1 answer
  • Which type of mixture could this illustration represent?
    9·2 answers
  • You are riding in an elevator that is accelerating upward. Suppose you stand on a scale. The reading on the scale is __________.
    6·2 answers
  • How many meters did the car go in the first 4 seconds?​
    10·1 answer
  • 4. Which of the following substance will cool off the fastest?
    5·1 answer
  • What is theory of relativity and why this theory made??????
    15·2 answers
  • A box has a momentum of 38.0 kg*m/s to the right. A 88.3 N force pushes it to the right for 0.338 s. What is the final momentum
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!