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seropon [69]
4 years ago
14

Can someone tell me how Antrax effects the body.

Chemistry
2 answers:
wel4 years ago
6 0
The effects<span> of A</span>nthrax<span> on the </span>body<span> include, shock, difficulty breathing, and intestinal inflammation. In serious cases, A</span>nthrax<span> can lead to inflammation of the areas surrounding the brain, and spinal cord, causing severe bleeding. This illness could also lead to death.
I hope this helps!</span>
suter [353]4 years ago
3 0
Anthrax effects the body by shock and by difficulty breathing
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Explain the phrase an “instrument is only as good as it's operator”
zubka84 [21]

Answer:

This is because an instrument literally does what the operator commanders it that is to say what the operator thinks of is what the instrument does and that's why the English say that a lazy man(operator) blames his tools(instrument)

4 0
3 years ago
Calculate the molar concentrations of H+ and OH− in solutions that have the following pH values:
Anastaziya [24]

Answer:

Explanation:

a )

pH = - log[ H⁺]

8.26 = - log[ H⁺]

[ H⁺] = 10⁻⁸°²⁶ mole / l

= 5.49 x 10⁻⁹ moles / l

[ H⁺] [OH⁻] = 10⁻¹⁴

[OH⁻] = 10⁻¹⁴ / 5.49 x 10⁻⁹

= .182  x 10⁻⁵ moles / l

b )

10.25 = - log[ H⁺]

[ H⁺] = 10⁻¹⁰°²⁵ mole / l

= 5.62 x 10⁻¹¹ moles / l

[ H⁺] [OH⁻] = 10⁻¹⁴

[OH⁻] = 10⁻¹⁴ / 5.62 x 10⁻¹¹

= .178 x 10⁻³ moles / l

c )

4.65 = - log[ H⁺]

[ H⁺] = 10⁻⁴°⁶⁵ mole / l

= 2.24 x 10⁻⁵ moles / l

[ H⁺] [OH⁻] = 10⁻¹⁴

[OH⁻] = 10⁻¹⁴ / 2.24 x 10⁻⁵

= .4464 x 10⁻⁹ moles / l

7 0
3 years ago
PLEASE HELP<br><br> Water is a ? .
Novosadov [1.4K]

Answer:Water, a substance composed of the chemical elements hydrogen and oxygen and existing in gaseous, liquid, and solid states. It is one of the most plentiful and essential of compounds. A tasteless and odorless liquid at room temperature, it has the important ability to dissolve many other substances.

5 0
4 years ago
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How can the rate of a reaction be increased?
Nana76 [90]
I think it may be A.
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4 0
3 years ago
Read 2 more answers
What is the Ka of a 0.0326 M solution of hydrofluoric acid with a pH of 3.94?
LenKa [72]

Answer:

Kₐ = 4.06 × 10⁻⁷

Explanation:

Step 1. <em>Calculate [H₃O⁺] </em>

\text{H}_{3}\text{O}^{+} = 10^{\text{-pH}}\text{ mol/L}

pH = 3.94

\text{H}_{3}\text{O}^{+} = 10^{-3.94}} \text{ mol/L}

[H₃O⁺] = 1.15 × 10⁻⁴ mol·L⁻¹

Calculate K_{\text{a}}

                             HF + H₂O ⇌          H₃O⁺          +          F⁻

I/mol·L⁻¹:           0.0326                          0                         0

C/mol·L⁻¹: 0.0326-1.15 × 10⁻⁴        +1.15 × 10⁻⁴           +1.15 × 10⁻⁴

E/mol·L⁻¹:         0.0325                    1.15 × 10⁻⁴            1.15 × 10⁻⁴

So, at equilibrium,

[H₃O⁺] = [F⁻] = 1.15 × 10⁻⁴ mol·L⁻¹

[HF] = 0.326 – 1.15 × 10⁻⁴  mol·L⁻¹ = 0.0325 mol·L⁻¹

Kₐ = {[H₃O⁺][F⁻]}/[HF]

Kₐ = (1.15 × 10⁻⁴ × 1.15 × 10⁻⁴)/0.0325

Kₐ = 1.32 × 10⁻⁸/0.0325

Kₐ = 4.06 × 10⁻⁷

This is <em>NOT</em> a solution of HF (Kₐ = 7.2 × 10⁻⁴). It is more likely a solution of carbonic acid (H₂CO₃; Kₐ₁ = 4.27 × 10⁻⁷).

8 0
3 years ago
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