Hey there!
Molar mass Na2SO4 = 142.04 g/mol
Number of moles:
n = m / mm
n = 25 / 142.04
n = 0.176 moles of Na2SO4
Therefore, use the Avogadro constant
1 mole Na2SO4 ------------------- 6.02x10²³ molecules
0.176 moles Na2SO4 ------------ molecules ??
0.176 x ( 6.02x10²³ ) / 1
=> 1.059x10²³ molecules of Na2SO4
hope this helps!
Answer is: freezing point is -0,226°C.
Answer is: the molal concentration of glucose in this solution is 1,478 m.
m(KCl) = 15 g.
n(KCl) = m(KCl) ÷ M(KCl).
n(KCl) = 15 g ÷ 74,55 g/mol.
n(KCl) = 0,2 mol
m(H₂O) = 1650 g ÷ 1000 g/kg = 1,65 kg.
b = n(KCl) ÷ m(H₂O).
b = 0,2 mol ÷ 1,65 kg = 0,122 m.
Kf(water) = 1,86°C/m.
ΔT = Kf(water) · b(solution).
ΔT = 1,86°C/m · 0,122 m.
ΔT = 0,226°C.
The compound given (i.e. 3,3-dimethyl-1-butanol) is primary alcohol (1°) because the functional group (-OH) shows that it is alcohol is attached to a primary carbon (i.e terminal carbon).
The oxidation of all primary alcohols results in the formation of aliphatic aldehyde(also known as alkanal).
Suppose, it is secondary alcohol;
The oxidation of secondary alcohol results in the formation of ketone(also known as alkanone).
When 3,3-dimethyl-1-butanol undergoes oxidation, the suffix "ol" in the alcohol changes to "al"
Therefore, 3,3-dimethyl-1-butanol changes to 3,3-dimethyl-1-butanal after undergoing oxidation.
In conclusion, the product when 3,3-dimethyl-1-butanol undergoes oxidation is: 3,3-dimethylbutanal.
As such, option 2 is correct.
Learn more about oxidation reaction here:
brainly.com/question/14863344?referrer=searchResults
Answer:
Density is defined as how tightly or loosely packed a substance is, or to the number of things or people in a certain area.