1) 0.89% m/v = 0.89 grams of NaCl / 100 ml of solution
=> 8.9 grams of NaCl in 1000 ml of solution = 8.9 grams of NaCl in 1 liter of solution
2) Molarity = M = number of moles of solute / liters of solution
=> calculate the number of moles of 8.9 grams of NaCl
3) molar mass of NaCl = 23.0 g /mol + 35.5 g/mol = 58.5 g / mol
4) number of moles of NaCl = mass / molar mass = 8.9 g / 58.5 g / mol = 0.152 mol
5) M = 0.152 mol NaCl / 1 liter solution = 0.152 M
Answer: 0.152 M
Answer:
true
Explanation:
H2O : 2 covalent bonds are established between O atom and 2 H atom (H--O--H) by mutual shearing of their valence electrons.
Opposing reactions are constantly occurring at equal rates
favoring the formation if fewer miles if gaseous products
The correct answer is B.
1 mol O2 x 15.999 O2/ 1 mol O2 = 15.999 O2
16 O2 when rounded.
Answer:
maybe 200g
I don't know thats just a guess
HOPE ITS TURE
