The first bullet is : Expression with subtraction
Second bullet: Use formula 8(7-2.5) to solve
Answer:
The largest printed area is 381.43 cm^2 .
Step-by-step explanation:
The width of the full poster = 500/x
Length of the printed area = l =x - 4
Width of the printed area = w = (500/x) - 2
Area of the printed space = (x - 4) × ((500/x) - 2)
Now, take derivative of the area
A' = (x - 4)×(-500/x^2) + ((500/x) - 2)
A' = (2000/x^2) - 2
A' = (2000-2x^2) / x^2
put derivative equal to zero like A' = 0
(2000-2x^2) / x^2 = 0
2000 = 2x^2
x^2 = 1000
x = 31.62
So, the length of the original poster is = x = 31.62 cm
The width of the full poster = 500/x = 15.81 cm
l = x - 4 = 27.62
w = 500/x - 2 = 13.81
Therefore, The area of space available for printing is = l × w
= 27.62 × 13.81 = 381.43 cm^2 .
Answer: 
Step-by-step explanation:
Given
Elisa run a total of 
miles on Saturday and Sunday.
If she runs 
miles on Saturday
Then, distance traveled on Sunday is given by
Answer:
Step-by-step explanation:
Assuming the rate of increase in the cost of tuition fee per year is linear. We would apply the formula for determining the nth term of an arithmetic sequence which is expressed as
Tn = a + (n - 1)d
Where
a represents the first term of the sequence.
d represents the common difference.
n represents the number of terms in the sequence.
From the information given,
a = $20500(amount in 2000)
From 2000 to 2018, the number of terms is 19, hence,
n = 19
T19 = 454120
Therefore,
454120 = 20500 + (19 - 1)d
454120 - 20500 = 18d
18d = 433620
d = 433620/18
d = 24090
Therefore, the equation that can be used to find the tuition y for x years after 2000 is expressed as
y = 20500 + 24090(x - 1)
To to estimate the tuition at this college in 2020, the number of terms between 2000 and 2020 is 21, hence
x = 21
y = 20500 + 24090(21 - 1)
y = 20500 + 481800
y = $502300
