Halogenation of ethane and bromine
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Answer: The percent yield for the is, 86.7 %
Explanation : Given,
Moles of = 2.36 mol
Moles of = 6.14 mol
First we have to calculate the moles of
The balanced chemical equation is:
From the reaction, we conclude that
As, 2 moles of react to give 6 moles of
So, 2.36 moles of react to give
mole of
Now we have to calculate the percent yield for the .
Experimental yield = 6.14 moles
Theoretical yield = 7.08 moles
Now put all the given values in this formula, we get:
Therefore, the percent yield for the is, 86.7 %