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Juliette [100K]
3 years ago
13

Which correctly identifies the mass and approximate weight of the same object on Earth?

Physics
1 answer:
Vladimir79 [104]3 years ago
4 0

Answer:

B.

Explanation:

w=mg

g=10m/s

hope this helps

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An ocean wave is an example of what type of wave​
Tanzania [10]

Answer:

It is called a surface wave (rayleigh wave) that transmits its energy with the wind blowing onto its surface.Hope this helps

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The most abundant climate type over the face of the earth is
erastovalidia [21]
It is Humid Continental but i could be wrong
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3 years ago
(a) A physicist performing a sensitive measurement wants to limit the magnetic force on a moving charge in her equipment to less
Free_Kalibri [48]

Answer:

q = 7.4 10⁻¹⁰ C

Explanation:

a) The magnetic force is given by the expression

        F = q v x B

Where the blacks indicate vectors, q is the electric charge, v at particle velocity and B the magnitude of the magnetic field. If the velocity is perpendicular to the magnetic field, the sine is 1

      F = q v B

Let's calculate the charge

      q = F / vB

      q = 1.00 10⁻¹² / 30.0 B

For the magnetic field of the earth we have a value between 25μT and 65μT, an intermediate value would be 45 μT, let's use this value.

     q = 1 10⁻¹² / (30 45 10⁻⁶)

    q = 7.4 10⁻¹⁰ C

b) In laboratories and modern electronics, currents of up to 1 10⁻⁶ A can be achieved without much difficulty, in advanced and research laboratories currents of up to 1 10⁻¹² can be managed. Load values ​​(coulomb) cannot they are widely used today for work, but 1 mA = 3.6C, so we see that getting loads with the value of 10⁻¹⁰ C implies very small current less than 1 10⁻¹³ A, which only in laboratories of Very specialized can be created. Consequently, from the above it would be difficult to find loads lower than the calculated

The electrostatic charge is the one created by the friction between two surfaces, it is an indicated charge, in this case it would be possible to have better wing loads found from 10⁻¹⁰C

4 0
3 years ago
Describe the limitations of the free body diagrams.
Olenka [21]

Answer:

Free-body diagrams are defined as the diagram that represents the direction and magnitude of all forces that act on an object.

There are some limitations of the free-body diagrams, that are:

  • The free-body diagram is based on coordinate system that increases the complexity of the diagram.
  • There are lot of forces acting on an object such as friction, gravity, drag, tension, and normal force and to calculate the end result, it is important to determine the correct direction of all the forces otherwise wrong direction of any one of the force can give the wrong answer.
  • Free-body diagrams do not depend on the size and shape of the body, that is why unable to calculate the rotation and torque.
8 0
3 years ago
A 25 newton force applied on an object moves it 50 meters. The angle between the force and displacement is 40.0°. What is the va
zloy xaker [14]

Answer:

<em>T</em><em>he value of work being done on the object is 958J.</em>

Explanation:

<em>Work</em><em> done</em><em> </em><em>is </em><em>equal</em><em> to</em><em> </em><em>force</em><em> </em><em>multiply</em><em> by</em><em> </em><em>distance,</em><em> </em><em>but </em><em>when</em><em> </em><em>the </em><em>angle</em><em> </em><em>is </em><em>between</em><em> </em><em>the</em><em> </em><em>force</em><em> </em><em>and</em><em> </em><em>distance</em><em> </em><em>work</em><em> </em><em>done=</em><em>Force</em><em> (</em><em>cos</em><em> </em><em>theta)</em><em> </em><em>×</em><em> </em><em>distance</em>

<em>Work</em><em> done</em><em> </em><em>=</em><em> </em><em>Force(</em><em>cos </em><em>theta</em><em>)</em><em> </em><em>×</em><em> </em><em>distance</em>

<em>Work</em><em> done</em><em> </em><em>=</em><em> </em><em>2</em><em>5</em><em>N</em><em>(</em><em>cos </em><em>4</em><em>0</em><em>.</em><em>0</em><em>°</em><em>)</em><em> </em><em>×</em><em> </em><em>5</em><em>0</em><em>m</em>

<em>Work</em><em> done</em><em> </em><em>=</em><em> </em><em>2</em><em>5</em><em>N</em><em>(</em><em>0</em><em>.</em><em>7</em><em>6</em><em>6</em><em>0</em><em>)</em><em> </em><em>×</em><em> </em><em>5</em><em>0</em><em>m</em>

<em>Work</em><em> done</em><em> </em><em>=</em><em> </em><em>19.15N </em><em>×</em><em> </em><em>5</em><em>0</em><em>m</em>

<em>Work</em><em> done</em><em> </em><em>=</em><em> </em><em>957.5J </em><em>=</em><em> </em><em>9</em><em>5</em><em>8</em><em>J</em>

<em>T</em><em>herefore</em><em> the</em><em> </em><em>value</em><em> of</em><em> </em><em>work</em><em> </em><em>being</em><em> </em><em>done </em><em>on </em><em>the</em><em> </em><em>object</em><em> </em><em>is </em><em>9</em><em>5</em><em>8</em><em>J</em><em>.</em>

3 0
2 years ago
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