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Vladimir79 [104]
3 years ago
15

A woman weighing 450 Newtons sits on the floor. She exerts a force on the floor of

Chemistry
1 answer:
ANEK [815]3 years ago
4 0

Answer: let me figure it out rlly quick

Explanation:

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Can someone answer that first this pls im lost
Alchen [17]
-Just look up “H2O lewis structure
-1.5
-Don’t know the VSEPR
-Polar Covalent
-Again, don’t know VSEPR
-Just look up H2O molecule
4 0
2 years ago
What is the molarity of a solution containing 501mL with 35g NaCl
Vesna [10]

Answer:

Data:

mass of solute: 35g of NaCl

m.mass of solute: 58g/mol

volume of solution: 501mL

Molarity=?

Explanation:

501ml = 0.5dm3

M= g of solute/m.mass of solute*vol of solution

M= 35/58*0.5

M=1.20

6 0
3 years ago
Choose a sport or sporting play. Describe the types of energy involved in playing the sport. State whether playing the sport is
mrs_skeptik [129]

Answer:

Doing a bungee jumping

Potential energy ---> Kinetic energy

Explanation:

3 0
3 years ago
B. The following reaction takes place in a basic solution. (7 points)
Natali5045456 [20]

<u>Answer:</u> The final equation has hydroxide ions which indicate that the reaction has occurred in a basic medium.

<u>Explanation:</u>

Redox reaction is defined as the reaction in which oxidation and reduction take place simultaneously.

The oxidation reaction is defined as the reaction in which a chemical species loses electrons in a chemical reaction. It occurs when the oxidation number of a species increases.

A reduction reaction is defined as the reaction in which a chemical species gains electrons in a chemical reaction. It occurs when the oxidation number of a species decreases.

The given redox reaction follows:

MnO_4^-(aq)+NO_2^-(aq)\rightarrow MnO_2(s)+NO_3^-(aq)

To balance the given redox reaction in basic medium, there are few steps to be followed:

  • Writing the given oxidation and reduction half-reactions for the given equation with the correct number of electrons

Oxidation half-reaction: NO_2^-+2OH^-\rightarrow NO_3^-+H_2O+2e^-

Reduction half-reaction: MnO_4^-+2H_2O+3e^-\rightarrow MnO_2+4OH^-

  • Multiply each half-reaction by the correct number in order to balance charges for the two half-reactions

Oxidation half-reaction: NO_2^-+2OH^-\rightarrow NO_3^-+H_2O+2e^-         ( × 3)

Reduction half-reaction: MnO_4^-+2H_2O+3e^-\rightarrow MnO_2+4OH^-             ( × 2)

The half-reactions now become:

Oxidation half-reaction: 3NO_2^-+6OH^-\rightarrow 3NO_3^-+3H_2O+6e^-

Reduction half-reaction: 2MnO_4^-+4H_2O+3e^-\rightarrow 2MnO_2+8OH^-

  • Add the equations and simplify to get a balanced equation

Overall redox reaction: 3NO_2^-+2MnO_4^-+H_2O\rightarrow 3NO_3^-+2MnO_2+2OH^-

As we can see that in the overall redox reaction, hydroxide ions are released in the solution. Thus, making it a basic solution

3 0
3 years ago
Please help i will mark brainliest which helps bring up youre rank
Elis [28]

Answer:

push or pull

Explanation:

3 0
3 years ago
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