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2 years ago

How can the rate constant be determined from the rate law?

Chemistry

1 answer:

Vinil7 [7]2 years ago

7 0

Answer:

B. The rate constant is the reaction rate divided by the concentration

terms.

Explanation:

The rate constant can be determined from the rate law because it is the reaction rate divided by the concentration terms. I hope I could help! :)

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a radioisotope has a half life of three hours how much of a 120g sample remains after 9 hours. what will the g amount be after 3

aksik [14]

$\huge\boxed{♔︎Answer♔︎}$

60g after 3 hours, 30g after 6 hours and 15g after 9 hours

Explanation:

Weight of the radioactive sample = 120g

half life time period = 3 hours

(a) The weight of sample after 3 hours

$\textsf{ No. of half lives} = \sf \cancel\frac{3}{3} = 1$

The fraction of sample left

$\sf { \frac{1}{2} }^{1} = \frac{1}{2}$

Mass of the sample left

$\sf \frac{1}{2} \times 120 = \cancel\frac{120}{2} = 60g$

60g of sample is left after 3 hours

(b) The weight of sample after 6 hours

$\textsf{ No. of half lives} = \sf \cancel\frac{6}{3} = 2$

The fraction of the sample left

$\sf { \frac{1}{2} }^{2} = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4}$

Mass of the sample left

$\sf \frac{1}{4} \times 120 = \cancel\frac{120}{4} = 30g$

30g of sample is left after 6 hours

$\textsf {No. of half lives} = \sf \cancel\frac{9}{3} = 3$

The fraction of sample left

$\sf { \frac{1}{2} }^{3} = \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} = \frac{1}{8}$

Mass of sample left

$\sf \frac{1}{8} \times 120 = \cancel \frac{120}{8} = 15g$

15g of sample is left after 9 hours.

3 0

2 years ago

Type the correct answer in the box. Express your answer to three significant figures.

satela [25.4K]

Answer:

The partial pressure of argon in the jar is 0.944 kilopascal.

Explanation:

Step 1: Data given

Volume of the jar of air = 25.0 L

Number of moles argon = 0.0104 moles

Temperature = 273 K

Step 2: Calculate the pressure of argon with the ideal gas law

p*V = nRT

p = (nRT)/V

⇒ with n = the number of moles of argon = 0.0104 moles

⇒ with R = the gas constant = 0.0821 L*atm/mol*K

⇒ with T = the temperature = 273 K

⇒ with V = the volume of the jar = 25.0 L

p = (0.0104 * 0.0821 * 273)/25.0

p = 0.00932 atm

1 atm =101.3 kPa

0.00932 atm = 101.3 * 0.00932 = 0.944 kPa

The partial pressure of argon in the jar is 0.944 kilopascal.

5 0

3 years ago

Mass = 35g Volume = 7cm3 What is the Density?

olga_2 [115]

Answer:

5 g/cm^3

Explanation:√3V=1.91293cm

7 0

3 years ago

URGENT!!! A car engine uses the combustion of fuel to move a system of gears that move its wheels. Not all of the fuel's energy

Jobisdone [24]

Answer:sound energy and thermal energy

Explanation: cause coochie man

5 0

3 years ago

Read 2 more answers

How does stem apply to science? (i swear if yall just answer for points ima lose it)

vova2212 [387]

STEM is an acronym meaning

Science

Technology

Engineering

Mathematics

One of the main focuses of STEM courses is on science, so you will be learning about various types of science

This is an approach at learning to have students learn all four types of subjects in one class, based on real world applications.

8 0

3 years ago