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3 years ago

Based on the context of paragraph 4, what are salient factors?

Chemistry

2 answers:

Stella [2.4K]3 years ago

4 0

Answer:

importent factors

Explanation:

The salient facts about something or qualities of something are the most important things about them: She began to summarize the salient features/points of the proposal. The article presented the salient facts of the dispute clearly and concisely. SMART Vocabulary: related words and phrases. Very important or urgent.

Kitty [74]3 years ago

3 0

Answer

The answer is a/important factors. Pls subscribe to Amiredagoat Yt in return.

Explanation:

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Chromium(III) oxide can be prepared by heating chromium(IV) oxide in vacuo at high temperature: 4Cr02 —2Cr2O3 +02 The reaction o

kkurt [141]

<u>Answer:</u> The theoretical yield and percent yield of chromium (III) oxide is 434.72 grams and 92.6 % respectively.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of $CrO_2$ = 480.1 g

Molar mass of $CrO_2$ = 84 g/mol

Putting values in equation 1, we get:

$\text{Moles of }CrO_2=\frac{480.1g}{84g/mol}=5.72mol$

For the given chemical equation:

$4CrO_2\rightarrow 2Cr_2O_3+O_2$

By Stoichiometry of the reaction:

4 moles of $CrO_2$ produces 2 moles of chromium (III) oxide

So, 5.72 moles of $CrO_2$ will produce = $\frac{2}{4}\times 5.72=2.86mol$ of chromium (III) oxide

Now, calculating the mass of chromium (III) oxide from equation 1, we get:

Molar mass of chromium (III) oxide = 152 g/mol

Moles of chromium (III) oxide = 2.86 moles

Putting values in equation 1, we get:

$2.86mol=\frac{\text{Mass of chromium (III) oxide}}{152g/mol}\\\\\text{Mass of chromium (III) oxide}=(2.86mol\times 152g/mol)=434.72g$

To calculate the percentage yield of chromium (III) oxide, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of chromium (III) oxide = 402.4 g

Theoretical yield of chromium (III) oxide = 434.72 g

Putting values in above equation, we get:

$\%\text{ yield of chromium (III) oxide}=\frac{402.4g}{434.72g}\times 100\\\\\% \text{yield of chromium (III) oxide}=\%$

Hence, the theoretical yield and percent yield of chromium (III) oxide is 434.72 grams and 92.6 % respectively.

7 0

2 years ago

a car is traveling at a speed of 55 mph the speed increased to 75 mph if the time needed to hange its speed is 4 seconds whats t

Savatey [412]

v = 75 mph = 33.52 m/s

u = 55 mph = 24.58 m/s

t = 4 sec

acceleration = v-u/t

= 33.52-24.58/4

= 8.94/4

= 2.235 m/s

6 0

2 years ago

Which of these best describes the relationship between the inner core, outer core, mantle, crust, asthenosphere, and lithosphere

torisob [31]

The question is incomplete, the complete question is;

Which of these best describes the relationship between the inner core, outer core, mantle, crust, asthenosphere, and lithosphere?

A: The coolest layers are farthest from the core.

B: The least dense layers are closest to the core.

C: The layers with the highest concentration of metals are closest to the crust.

D: The layers that remain in a molten state are closest to the crust.

Answer:

The coolest layers are farthest from the core.

Explanation:

When we talk about the internal structure of Earth, we mean the subdivisions of the solid Earth, that is, the concentric spherical layers that marks out the structure of the solid Earth.

The inner core is the innermost part of the earth's core and is known to have extremely high temperature. This high temperature steadily decreases as you approach the earth's surface.

Hence, the coolest layers are farthest from the core.

3 0

2 years ago

Which of the following is not the same as 2.97 milligrams? 0.0000297 kg, 0.00297 g, 0.297 ch

Travka [436]

the correct answer its 0.002975

4 0

3 years ago

Read 2 more answers

How much heat is released when 105 g of steam at 100.0°C is cooled to ice at -15.0°C? The enthalpy of vaporization of water is 4

vitfil [10]

Answer:

MgCal2=Cal2

Explanation:

5 0

3 years ago