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4 years ago

Which is directly proportional to your weight on a planet's surface?

Physics

2 answers:

Mnenie [13.5K]4 years ago

6 0

Answer:

D your mass the mass of the planet .

Explanation:

Oduvanchick [21]4 years ago

5 0

D. Your mass and the mass of the planet

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A student is about to sled down a hill. He stands on a hill which is 30 meters tall and he weighs 40kg what is his GPE

PolarNik [594]

Answer:

11760J

Explanation:

Given parameters:

Height of hill = 30m

Weight = 40kg

Unknown:

Gravitational potential energy = ?

Solution:

To find the gravitational potential energy, it is the energy due to the position of a body;

G.PE = mgh

m is the mass

g is the acceleration due to gravity

h is the height

Now insert the parameters and solve;

G.PE = 40 x 9.8 x 30 = 11760J

3 0

3 years ago

A child in danger of drowning in a river is being carried down-stream by a current that flows uniformly with a speed of 2.20 m/s

zmey [24]

Answer:

The angle is 65.6°.

Explanation:

Given that,

Speed = 2.20 m/s

Distance from the shore= 500 m

Distance from the bottom= 1100 m

Speed of boat = 7.30 m/s

According to figure,

We need to calculate the angle with shore

Using formula of angle

$\tan\theta=\dfrac{y}{x}$

Put the value into the formula

$\tan\theta=\dfrac{500}{1100}$

$\theta=\tan^{-1}(\dfrac{500}{1100})$

$\theta=24.4^{\circ}$

We need to calculate the angle

$\alpha=90-\theta$

Put the value into the formula

$\alpha=90-24.4$

$\alpha=65.6^{\circ}$

Hence, The angle is 65.6°.

5 0

3 years ago

Find the value of T1 if 1 = 30°, 2 = 60°, and the weight of the object is 139.3 newtons.

Lelechka [254]

Answer:

Option A (69.56 newtons) is the appropriate solution.

Explanation:

According to the question,

On the X-axis,

⇒ $T_1Cos30^{\circ}-T_2Cos60^{\circ}=0$

or,

$T_1Cos 30^{\circ}=T_2Cos60^{\circ}$

On substituting the values, we get

$T_1\times \frac{\sqrt{3} }{2}=T_2\times \frac{1}{2}$

$T_1\times \sqrt{3} =T_2$ ....(equation 1)

On the Y-axis,

⇒ $T_1Sin30^{\circ}+T_2Sin60^{\circ}=139.3 \ N$

$\frac{T_1}{2} +\frac{\sqrt{3} }{2} =139.2 \ N$

$T_1+\sqrt{3}T_2=139.2\times 2$

From equation 1, we get

$T_1+\sqrt{3}\times \sqrt{3}T_1 =278.4 \ N$

$T_1+3T_1=278.4 \ N$

$4T_1=278.4 \ N$

$T_1=\frac{278.4}{4}$

$=69.6 \ N$

6 0

3 years ago

A car travels at 40km/hr for 2 hours and at 55 km/hr for 2 hours. How far has the car traveled? What is its average velocity?

anastassius [24]

So if a car was moving 40km/hr, it means in 1 hour, the car will travel 40km. Since the car goes for 2 hours, the car will have traveled for 80 miles. Same.for the car going 55km/hr for 2 hours. 55 times 2 is 110km. 110 + 80 = 190km total. You can find the average velocity by by the distance traveled divided by how much time elapsed. so 190 divided by 4 is 47.5. So the distance traveled is 190km, and the average velocity is 47.5

8 0

3 years ago

John and Caroline go out for a walk one day. This graph represents their distance from home.

vivado [14]

Answer:

C) They walked in one direction, then they were still, then they walked in the opposite direction.

Explanation:

John and Caroline go out for a walk one day. This graph represents their distance from home.c According to the graph they walked with almost same in both the direction.

First they walked in one direction and travel 30 meter in same direction then they were still for some time. Then they walked in the opposite direction for 30 meter. They walked in both the direction with approximately equal speed.

Thus, Option C is correct.

5 0

3 years ago

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