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lara [203]
2 years ago
5

How much energy is released if a sample loses 0.001 kg mass through radioactive decay?

Chemistry
2 answers:
stealth61 [152]2 years ago
4 0

Explanation:

because the energy it can't be calculated

Aleks04 [339]2 years ago
4 0
The energy released by a decay in a 50.0-
q sample of 23994Pu is to be used to heat
4.40 kg of water.
Part A
Assuming all the energy released by the
radioactive decay goes into heating the water,
find how much the temperature of the water
increases in 1 h.
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A gas takes up a volume of 35 L, and has a pressure of 4.8 atm. What is the new pressure of
joja [24]

Answer:

7.3 atm

Explanation:

- Use the formula P1V1 = P2V2

- Rearrange formula and then plug in values.

- Hope this helped! Let me know if you need more help or a further explanation.

3 0
3 years ago
2H2(g)+O2(g)→2H2O(l)
Zina [86]

Answer:

6.4g

Explanation:

32g of O2 produce 36g of H2O/5.70g of O2 produce x the answer is 6.4g

4 0
3 years ago
What is weathering? Please explain in your own words.
Annette [7]
To slowly erode and crumble.
8 0
3 years ago
How would you describe the following chemical reaction?
GREYUIT [131]

Answer:

B

Explanation:

The normal way to express an energy reaction is to put the energy on the left. Then you can make a rule.

  • If the energy on the left is plus then the reactants require energy. The reaction is endothermic -- energy is taken from the environment.
  • If the energy is minus when it is on the left. then the reactants give up energy. The reaction is exothermic and energy is given to the environment.

2CO(g)+O2(g) - energy --> 2CO2(g)

Exothermic

4 0
2 years ago
Consider the following reaction where Kc = 34.5 at 1150 K:2SO2(g) + O2(g) 2SO3(g)A reaction mixture was found to contain 4.77×10
sukhopar [10]

Answer:

Explanation:

[ so₃] = 4.37 x 10⁻²

[so₂] = 4.77 x 10⁻²

[ o₂] = 4.55 x 10⁻²

Qc = (4.37)²x10⁻⁴ /(4.77)².(4.55) x 10⁻⁶ =18.44

Qc is less than Kc hence in order to reach equilibrium more of so₃ will be produced . Statement 1 is true.

Kc is always constant . Statement 2 is false.

Statement 3 is false because statement 1 is true.

Qc Is smaller than Kc . So statement 4 is false.

The reaction is not in equilibrium. Statement 5 is false.

3 0
3 years ago
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