Considering the definition of pOH and strong base, the pOH of the aqueous solution is 1.14
The pOH (or potential OH) is a measure of the basicity or alkalinity of a solution and indicates the concentration of ion hydroxide (OH-).
pOH is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:
pOH= - log [OH⁻]
On the other hand, a strong base is that base that in an aqueous solution completely dissociates between the cation and OH-.
LiOH is a strong base, so the concentration of the hydroxide will be equal to the concentration of OH-. This is:
[LiOH]= [OH-]= 0.073 M
Replacing in the definition of pOH:
pOH= -log (0.073 M)
<u><em>pOH= 1.14 </em></u>
In summary, the pOH of the aqueous solution is 1.14
Learn more:
The equation is x/25=3.2
*25 *25
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x=80g
Answer:
Explanation:
In one mole of liquid HF , no of molecules is 6.02 x 10²³.
Each molecule forms two hydrogen bonds on an average so no of hydrogen bonds per mol ih HF is
2 x 6.02 x 10²³.
= 12.04 x 10²³ .
In water no of hydrogen bonds per molecule of water is 4 . So in one mole of water no of hydrogen bonds is
4 x 6.02 x 10²³.
= 24.08 x 10²³ .
The answer is "<span>An atomic nucleus is positively charged because it is composed of protons". An atomic nucleus actually contains nucleons which are made up of both protons and neutrons. Since neutrons are neutral or have no charge, the charge of an atomic nucleus mainly relies on the positive charge of the protons.</span>
<h3>
Answer:</h3>
0.342 mol Ca
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
13.7 g Ca
<u>Step 2: Identify Conversions</u>
Molar Mass of Ca - 40.08 g/mol
<u>Step 3: Convert</u>
- Set up:
- Multiply/Divide:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
0.341816 mol Ca ≈ 0.342 mol Ca
