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allochka39001 [22]
3 years ago
5

Acar moving at 25 m/s slams on its brakes and comes to rest in a time interval of 5 sec. Calculate the average acceleration of t

he car​
Physics
1 answer:
Artyom0805 [142]3 years ago
8 0

Answer:

Explanation:

acceleration =\frac{v1 -v2}{t} =\frac{25-0}{5}= 5

since the car stoped do its final velocity or v2 is equal 0

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Maximum range of a projectile is 1.6 m. Then the velocity of projection will be..... (g=10m/s)
qaws [65]

Answer:

4 m/s

Explanation:

From the question given above, the following data were obtained:

Maximum range (Rₘₐₓ) = 1.6 m

Acceleration due to gravity (g) = 10 m/s²

Initial velocity (u) =?

The initial velocity of the projectile can be obtained as follow:

Rₘₐₓ = u² / g

1.6 = u² / 10

Cross multiply

u² = 1.6 × 10

u² = 16

Take the square root of both side

u = √16

u = 4 m/s

Therefore, the velocity of the projectile is 4 m/s

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3 years ago
Waves transfer heat by the process of ______________.<br><br> convection<br><br> radiation
alexandr1967 [171]
Radiation transfers heat by electromagnetic waves
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6. Mithra is an unknown planet that has two airless moons. A and B, in circular orbits around it.
Ainat [17]

The acceleration of gravity on Moon B is D) 0.25 m/s2

Explanation:

The data listed in the problem are not clear: find them in the table attached.

The acceleration of gravity on a planet is given by the following equation:

g=\frac{GM}{R^2}

where:

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2} is the gravitational constant

M is the mass of the planet

R is the radius of the planet

Here we want to find the acceleration of gravity on the surface of Moon B, which has the following data:

M=1.5\cdot 10^{20} kg (mass)

R=2.0\cdot 10^5 m (radius)

And substituting into the equation, we find:

g=\frac{(6.67\cdot 10^{-11})(1.5\cdot 10^{20})}{(2.0\cdot 10^5)^2}=0.25 m/s^2

Learn more about gravity:

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4 0
3 years ago
Please help with these questions. All questions are in the image.​
S_A_V [24]

1) Average speed

2) Displacement

Explanation:

1)

Speed is a scalar quantity which gives a measure of how fast a body is moving. It is equal to the ratio between the distance travelled by an object and the time taken to cover that distance:

speed = \frac{d}{\Delta t}

where

d is the distance covered

\Delta t is the time taken

It is important to note that being a scalar, speed does not have any direction. Moreover, distance is also a scalar quantity, which corresponds to the total length of the path covered by the object, regardless on the direction taken.

So, the equation "travelled distance/elapsed time" corresponds to the average speed. (where the term average refers to the fact we are not measuring the speed at a specific instant in time, but on a certain time interval \Delta t.

2)

Velocity is a vector quantity, so it has both a magnitude and a direction.

The magnitude of the velocity is given by:

velocity=\frac{\Delta x}{\Delta t}

where

\Delta x is the change in position (or displacement) of the object

\Delta t is the time taken

And the direction of the velocity corresponds to the direction of the displacement.

We must note that while distance does not depend on the direction, displacement does. In fact, displacement measures the difference between the initial and final position of the object.

Therefore, the equation "change in position / elapsed time" is equal to the average velocity.

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4 0
4 years ago
What are two ways gravity is affected?​
andreev551 [17]

Answer: two way gravity is affected if somethings weight is doubled or grtavity gets weaker with distance

Explanation:

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3 years ago
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