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kvv77 [185]
3 years ago
5

What is - 10°F in degrees Celsius

Chemistry
2 answers:
Anon25 [30]3 years ago
6 0

Answer:

-23.333 °C

Explanation:

(-10°F − 32) × 5/9 = -23.33°C

Yanka [14]3 years ago
5 0

Answer:

The answer is

<h2>- 23.33 °C </h2>

Explanation:

To convert from degree Celsius to degrees Fahrenheit we use the formula

\degree C = (\degree F - 32) \times  \frac{5}{9}  \\

Where

°C is the temperature in degree Celsius

°F is the temperature in degree Fahrenheit

From the question

°F = - 10°F

It's equivalent in degree Celsius is

°C = ( - 10 - 32) \times  \frac{5}{9}  \\  =  -  42 \times  \frac{5}{9}  \\  =  -  \frac{70}{3}  \:  \:  \:  \:  \:  \:  \:  \:  \\  =  - 23.333...

We have the final answer as

<h3>- 23.33 °C </h3>

Hope this helps you

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Information-
tekilochka [14]

Answer:

So first thing to do in these types of problems is write out your chemical reaction and balance it:

Mg + O2 --> MgO

Then you need to start thinking about moles of Magnesium for moles of Magnesium Oxide. Based on the above equation 1 mole of Magnesium is needed to make one mole of Magnesium Oxide.

To get moles of magnesium you need to take the grams you started with (.418) and convert to moles by dividing by molecular weight of Mg (24.305), this gives you .0172 moles of Mg.

The theoretical yield would be the assumption that 100% of the magnesium will be converted into Magnesium Oxide, so you would get, based on the first equation, .0172 mol of MgO. Multiplying this by the molecular weight of MgO (24.305+16) gives us .693 g of MgO.

The percent yield is what you actually got in the experiment, and for this you subtract off the total mass from the crucible mass, or 27.374 - 26.687, which gives .66 g of MgO obtained.

Percent yield is acutal/theoretical, .66/.693, or 95.24%.

I'll let you do the same for the second trial, and average percent yield is just an average of the two trials percent yield.

Hope this helps.

6 0
3 years ago
Solutes lower the freezing point of water by:
il63 [147K]
Water molecules are constantly moving in Ice they move slower and are more tightly packed together and move at a slower pace to lower the freezing point you would have to find a solute that makes it harder for water to form crystals 
7 0
3 years ago
To make a sarurated solution, 36 g of sodium chloride is dissolved in 100 g of water at 293 k . Find its concentration at this t
nexus9112 [7]

Answer:

The answer is "26.47\%"

Explanation:

Sodium chloride  solute mass=36 \ g

Solvent water mass=100\ g

Calculating the solution mass = Solute mass  + solvent mass

                                                  = 36\ g +100\ g\\\\ = 136\ g\\\\

Calculating the percentage of concentration:

= \frac{solute\ mass}{solvent\ mass} \times 100\\\\=\frac{36\ grm}{136\ grm} \times 100\\\\=0.2647 \times 100\\\\=26.47 \%

3 0
3 years ago
A piece of iron is heated with a torch to a temperature of 603 k.
Mazyrski [523]
This question asks to compare the energy emitted by a piece of iron at T = 603K with the energy emitted by the same piece at T = 298K.

Then you need to use the Stefan–Boltzmann Law

That law states that energy emitted (E) is proportional to fourth power of the  to the absolute temperature (T), this is E α T^4 (the sign α is used to express proportionallity.

Then E (603) / E (298) = [603K / 298K]^4 = 16,8

Which meand that the Energy emitted at 603 K is 16,8 times the energy emitted at 298K.


5 0
3 years ago
PLEASE ANWSER CORRECTLY!! I WILL MARK BRAINIEST!!
kobusy [5.1K]

Answer:

I Think It's The Second One

Tell Me If I'm Wrong

7 0
3 years ago
Read 2 more answers
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