What are the products of the light reactions that are subsequently used by the calvin cycle?
1 answer:
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Answer: North of east
Explanation:
Given
Research station is 9.6 km away in North of east
after travelling 3.1 km north of east
Position vector of safari after 3.1 km is
Position vector if had traveled correctly is
Now applying triangle law of vector addition we can get the required vector
Direction is given by
Answer:
a) v(2) = 2m/s, v(3) = -2m/s
b) speed at t = 2s is 2m/s
speed at t = 3s is 2m/s
c) 0 m/s
Explanation:
We can take the derivative of x(t) to find the equation of velocity
v(t) = x'(t) = 10 - 4t
(a) v(2) = 10 - 4*2 = 10 - 8 = 2 m/s
v(3) = 10 - 4*3 = 10 - 12 = -2 m/s
(b) The speed would be the same as velocity without the direction
speed at t = 2s is 2m/s
speed at t = 3s is 2m/s
(c) The average velocity between t = 2s and t = 3s is distance it travels over period of time