1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
elixir [45]
2 years ago
13

According to Newton's second law of motion, if we have a rigid, unchanging mass and we observe it accelerating, what must be hap

pening? Question 2 options: A force is being applied to the mass No force was or is being applied to the mass The mass MUST be changing A force was not applied.
Physics
1 answer:
kkurt [141]2 years ago
8 0

The force is applied to the accelerating object that has a constant mass. Option A is correct.

<h3>What does Newton's second law of motion state?</h3>

The force applied to the object is the product of its mass and acceleration.

F = ma

Where,

F - force

m- mass

a - acceleration

From the equation, the force and the acceleration are in a proportional relation. The mass is not changing as given in the question.

Therefore, the force is applied to the accelerating object that has a constant mass.

Learn more about Acceleration:

brainly.com/question/2437624

You might be interested in
A 15 m uniform ladder weighing 500 N rests against a frictionless wall. The ladder makes a 60° angle with horizontal. (a) Find t
scoray [572]

Answer:

a)    F₁ = 267.3 N,   N₁ = 1300 N,  b)    μ = 0.324

Explanation:

For this exercise we use the rotational equilibrium condition, we have a reference system is the floor and the anticlockwise rotations as positive, in the adjoint we can see a diagram of the forces

           

let's use subscript 1 for the ladder and 2 for the firefighter

            ∑ τ = 0

          -W₁ x₁ - W₂ x₂ + N₁ y = 0

           N₁ = \frac{W_1 x_1 + W_2 x_2}{y}          (1)

the center of mass of the ladder is at its geometric center,

d = L / 2 = 15/2 = 7.5 m

         cos 60 = x₁ / d₁

         x₁ = d₁ cos 60

         x₁ = 7.5 cos 60

         x₁ = 3.75 m

for the firefighter d₂ = 4 m

         cos 60 = x₂ / d₂

         x₂ = d₂ cos 60

          x₂ = 4 cos 60 = 2 m

for the fulcrum d₃ = 15 m

         sin 60 = y / d₃

         y = d₃ sin 60

         y = 15 sin 60

         y = 13 m

we look for the Normal by substituting in equation 1

         N₂ = \frac{500 \ 3.75 \ + 800 \ 2}{13}

         N₂ = 267.3 N

now let's use the translational equilibrium relations

 X axis

           F₁ - N₂ = 0

           F₁ = N₂

           F₁ = 267.3 N

Axis y

          N₁ - W₁ -W₂ = 0

          N₁ = W₁ + W₂

          N₁ = 500 + 800

          N₁ = 1300 N

b) for this case change the firefighter's distance d₂ = 9 m

          x₂ = 9 cos 60

          x₂ = 4.5 m

we substitute in 1

          N₂ = \frac{500 \ 3.75 \ + 800 \ 4.5}{13}  

          N₂ = 421.15 N

of the translational equilibrium equation on the x-axis

          fr = F₁ = N₂

          fr = 421.15 N

friction force has the expression

          fr = μ N

in this case the reaction of the Earth to the support of the ladder is N1 = 1300N

          μ = fr / N₁

          μ = 421.15 / 1300

          μ = 0.324

8 0
2 years ago
Using a 683 nm wavelength laser, you form the diffraction pattern of a 1.1 mm wide slit on a screen. You measure on the screen t
n200080 [17]

Answer:

10.2 m

Explanation:

The position of the dark fringes (destructive interference) formed on a distant screen in the interference pattern produced by diffraction from a single slit are given by the formula:

y=\frac{\lambda (m+\frac{1}{2})D}{d}

where

y is the position of the m-th minimum

m is the order of the minimum

D is the distance of the screen from the slit

d is the width of the slit

\lambda is the wavelength of the light used

In this problem we have:

\lambda=683 nm = 683\cdot 10^{-9} m is the wavelength of the light

d=1.1 mm = 0.0011 m is the width of the slit

m = 13 is the order of the minimum

y=8.57 cm = 0.0857 m is the distance of the 13th dark fringe from the central maximum

Solving for D, we find the distance of the screen from the slit:

D=\frac{yd}{\lambda(m+\frac{1}{2})}=\frac{(0.0857)(0.0011)}{(683\cdot 10^{-9})(13+\frac{1}{2})}=10.2 m

6 0
3 years ago
Read the scenario below and answer the question that follows. Randall is hiring cooks for his restaurant. The first applicant is
Talja [164]
Randall has unconscious assumption that attractive people are more competent
4 0
2 years ago
PLEASE HELP!! I’ll give brainliest pls
marin [14]

Answer:

A

Explanation:

houses use alternating current source

6 0
2 years ago
A cart is pulled by a force of 250 N at an angle of 35° above the horizontal. The cart accelerates at 1.4 m/s2. The free-body di
Pachacha [2.7K]

Answer:

m=146.277kg which is rounded to 146kg

Explanation:

Remember that F=ma

But F represents not 250N, but 250cos(35)N since the force is being pulled above the horizontal.

So 250cos(35)=204.7880111 approximately, and since a=1.4m/s^2, we have 204.7880111=m(1.4m/s^2). Then we divide both sides by the acceleration to get the mass. So m=146.2771508kg which the nearest number is 146kg

Mass is always in kg, unless stated otherwise.

4 0
2 years ago
Read 2 more answers
Other questions:
  • An object of mass 20 kg is raised vertically through a distance of 8.0 m above ground level. Using g=10 m/s^2 what is the potent
    10·1 answer
  • A double star has two components of equal brightness, each with a magnitude of 8.34. if these stars are so close together that t
    5·1 answer
  • A 30-m-long rocket train car is traveling from Los Angeles to New York at 0.5c when a light at the center of the car flashes. Wh
    6·1 answer
  • What is the solar process that results in the production of energy? A. nuclear fission B. nuclear fusion C. convection D. radiat
    5·2 answers
  • 1 kg ball rolls off a 33 m high cliff, and lands 23 m from the base of the cliff. Express the displacement and the gravitational
    7·1 answer
  • A charge of 50 µC is pushed by a force of 25 µN a distance of 15 m in an electric field. What is the electric potential differen
    6·1 answer
  • if a body moves with 20 km per hour in first 1 hour 30 km per hour in second one hour 40 kilometre per hour in third one hour wh
    12·1 answer
  • When you stand up on your feet your feet cover an area of about 0.2 m2. Your feet push on the ground with a pressure of 50 lbs f
    12·1 answer
  • ¿por qué los buzos, cuando emergen con urgencia, deben exhalar continuamente durante el ascenso?
    7·1 answer
  • A car is driving directly north on the freeway at a speed of 119 km/h and a truck is leaving the freeway driving 87.7 km/h in a
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!