I think it's C. if we're talking about a rover.
But if it's a rocket that's computerized and automatic (synonym of unmanned)... Then it's B.
Answer:
answer c. come easy dear.
Explanation:
Acceleration is change in velocity over change in time.
a = Δv / Δt
a = (10 m/s − 5 m/s) / 4 s
a = 1.25 m/s²
Work = force × distance
First, find the distance traveled.
v² = v₀² + 2aΔx
(10 m/s)² = (5 m/s)² + 2 (1.25 m/s²) Δx
Δx = 30 m
Now find the work:
W = (600 kg × 1.25 m/s²) (30 m)
W = 22,500 J
Alternative, work = change in energy.
W = ΔKE
W = ½ mv² − ½ mv₀²
W = ½ m (v² − v₀²)
W = ½ (600 kg) ((10 m/s)² − (5 m/s)²)
W = 22,500 J
We are given with 98 Newton weight of an object on the surface of the earth with an acceleration equal to 9.8 m/s2. This means the mass of the object is equal to 98/9.8 or 10 kg. Hence the weight of the object 10,000 kilometers above sea level where acceleration is 1.49 m/s2 is 14.9 Newtons.
